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horsena [70]
3 years ago
5

The process of predicting values that extend beyond the range of data points is called (5 points)

Physics
1 answer:
k0ka [10]3 years ago
7 0

Answer:

The answer is B extrapolation

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A 762 kg car experiences a braking force of 9045 N and skids to a stop in 4.3 seconds. What is the speed of the car just before
PilotLPTM [1.2K]

Answer:

The solution for this problem is:

We will be using the formula for force which is F = ma 

=>10,000 = 2000 * a 

but we need to solve for acceleration so divide both sides by 2000, we will get:

=>a = 5 m/s^2 

Let the initial velocity was u m/s 

=>By v = u - at 

=>0 = u - 5 x 6 

Since acceleration is constant the velocity can be computed by multiplying the acceleration by 6 seconds. 

=>u = 30 m/s

Explanation:

6 0
3 years ago
En un barrio un estudiante observa un roedor en medio de dos postes, los cuales están comunicados por un solo cable de fibra ópt
castortr0y [4]

Answer:

7 Newton

Explanation:

Dado

Longitud de la cuerda = 50 m

El cable se dobla en 0,058 m.

Masa de roedor = 350 gramos = 0,35 kg

T = m * a + m × v2 / r

Sustituyendo los valores dados obtenemos

T = 0,35 (10 + 10)

T = 0,35 * 20

T = 7 Newton

4 0
3 years ago
This diagram represents a top-down view of an experiment on a table. The 250g and 100g masses are falling and are pulling the bl
nata0808 [166]
The answer should be B: 500g of mass on bottom.
7 0
4 years ago
Read 2 more answers
A rock, with a density of 3.55 g/cm^3 and a volume of 470 cm^3, is thrown in a lake. a) What is the weight of the rock out of th
SIZIF [17.4K]

Answer:

a) Weight of the rock out of the water = 16.37 N

b) Buoyancy force = 4.61 N

c) Mass of the water displaced = 0.47 kg

d) Weight of rock under water = 11.76 N

Explanation:

a) Mass of the rock out of the water = Volume x Density

   Volume = 470 cm³

   Density = 3.55 g/cm³

   Mass = 470 x 3.55 = 1668.5 g = 1.6685 kg

   Weight of the rock out of the water = 1.6685 x 9.81 = 16.37 N

b) Buoyancy force = Volume x Density of liquid x Acceleration due to gravity.

   Volume = 470 cm³

   Density of liquid = 1 g/cm³

   \texttt{Buoyancy force}= \frac{470\times 1\times 9.81}{1000} = 4.61 N

c) Mass of the water displaced = Volume of body x Density of liquid

   Mass of the water displaced = 470 x 1 = 470 g = 0.47 kg

d) Weight of rock under water = Weight of the rock out of the water - Buoyancy force

   Weight of rock under water = 16.37 - 4.61  =11.76 N

3 0
3 years ago
a balloon inflated in a room at 297k has a volume of 4.00 l. the balloon is then heated to a temperature of 331 k. what is the n
Naddika [18.5K]
V2 = 4.4579 L

Since pressure is constant, use Charle’s law.
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.

V(olume) 1 = V(olume) 2
————— —————
T(emperature) 1 T(emperature)2

4.00 L = V2
———- ———
297 K 331 K

Cross multiply
(4.00 L x 331 K) = (297 K x V2)
Simplify
1324 L/K = 297 K x V2
Isolate V2 by dividing out 297 K
1324 L/K = V2
————
297 K
(This cancels out the kelvin and leaves you with Liters as the volume measure)

V2 = 4.4579 L

Round to significant digits if required
7 0
2 years ago
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