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Marina CMI [18]
4 years ago
10

What influences the degree to which light is refracted when it passes from one medium to another?

Physics
1 answer:
saveliy_v [14]4 years ago
8 0

Answer: The angle and wavelength at which the light enters a substance and the density of that substance determine how much the light is refracted.

HOPE THIS HELPS

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Supply the missing force necessary to achieve equilibrium. Show your work.
Mumz [18]

<u>Analysing the Question:</u>

We know that equilibrium is the state of a body when it has equal and opposite forces being applied on it

In this case, a net downward force of 496N is being applied and a net upward force of (106 + 106 + 142 + x) N

<u>Finding the missing force:</u>

Since we have to achieve equilibrium, the net upward forces have to be equal to the net downward forces

So,  (106 + 106 + 142 + x) = 496

354 + x = 496

x = 496 - 354

x = 142 N

Therefore, the missing force is 142 N

8 0
3 years ago
Which does not describe a physical change happening to water?
VARVARA [1.3K]
On your list you can easily identify by knowing which is not a chemical change.

A physical change is a change not involving the material composition of the water. e.g. (melting, solidifying, evaporation). As long as the change does not change the molecular composition of the water which is H20 it is physical change.
6 0
3 years ago
1. Two balloons are charged with an identical quantity and type of charge: -6.25C. They are held apart at a separation distance
Degger [83]

Answer:

The electric force between them is 878.9 N

Given:

Identical charge C

Separation between two charges  m

For finding the electrical force,

According to the coulomb's law

Here, force between two balloons are repulsive because both charges are same.

Where    N  Therefore, the electric force between them is 878.

Explanation:

4 0
2 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a –80-nC charge at x = –4 m on
leva [86]

Answer:48 V

Explanation:

Given

Three charged particle with charge

q_1=50\ nC at y=6\ m

q_2=-80\ nC at x=-4\ m

q_3=70\ nC at y=-6\ m

Electric Potential is given by

V=\frac{kQ}{r}

Distance of q_1 from x=8\ m

d_1=\sqrt{6^2+8^2}

d_1=\sqrt{36+64}

d_1=10\ m

similarly d_2=8-(-4)

d_2=12\ m

d_3=\sqrt{(-6)^2+8^2}

d_3=\sqrt{36+64}

d_3=10\ m

Potential at x=8\ m is

V_{net}=\frac{kq_1}{d_1}+\frac{kq_2}{d_2}+\frac{kq_3}{d_3}

V_{net}=k[\frac{q_1}{d_1}+\frac{q_2}{d_2}+\frac{q_3}{d_3}]

V_{net}=9\times 10^9[\frac{50}{10}-\frac{80}{12}+\frac{70}{10}]\times 10^{-9}

V_{net}=9\times 5.33

V_{net}=47.97\approx 48\ V

5 0
3 years ago
Please help i have to pass
lana66690 [7]
Hey kid!

So let’s not make this complicated. Obviously this word problem is wanting to confuse you with all these fancy words but, we’re not letting that get in the way!

Our two numbers are 6 and 12. If you think about it... 12 divided by 6 equals 2!!
That would make your answer B) 2m.

Happy to help!
~Brooke❤️
3 0
3 years ago
Read 2 more answers
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