The answer to this item is letter "C. counterculture". Those who are believers in this concept persuade individuals to run counter or move away from the norms that are preset or established in the society. The counterculture may also pertain to certain beliefs, styles, values, and attitudes that is varied from the prevailing culture.
Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3
= 5 3 2
x_{f} = 45 m
we substitute

v = 15 m / s
False does not last that long
<span>The formulas are,
Impulse = mv-mu ....... (1)
v^2 = u^2 + 2as .......... (2)
We know that,
u=0
a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2
s=19.6
sub (2) we get,
v^2 = 0+ 2*9.81*19.6
v^2 = 2*9.81*19.6
v^2 = 384.552
v = 19.6099
v = 19.61 m/s
Sub v=19.61 m/s in (1) we get,
Impulse = mv - mu
we know that u=0; v= 19.61 m/s; m= 3.00 kg
Impulse = 3(19.61) - 3(0)
Impulse = 58.83-0
Impulse = 58.83 Ns.
Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>