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Alexxandr [17]
3 years ago
11

Solve for In(5z + 7) – 8

Mathematics
1 answer:
Elden [556K]3 years ago
6 0

Step-by-step explanation:

In×5z+In×7

=1.67z +1.95-8

=1.67z-6.05

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Musya8 [376]
The answer to your question is 10/3
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Solve the quadratic equation by completing the square. 6x2 + 4x - 5 = 0
Nikitich [7]

Answer:

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

Step-by-step explanation:

Quadratic Equation given:

6x^2 + 4x - 5 = 0

Start dividing both sides by 6.

$\frac{6}{6} x^2 +\frac{4}{6} x - \frac{5}{6}  = \frac{0}{6} $

$x^2 +\frac{2}{3} x - \frac{5}{6}  = 0 $

$x^2 +\frac{2}{3} x = \frac{5}{6} $

Once, $\left( \frac{2}{3} \cdot \frac{1}{2} \right)^2=\frac{1}{9} $

$x^2 +\frac{2}{3} x+\frac{1}{9}  = \frac{5}{6}+\frac{1}{9}  $

$\left(x+\frac{1}{3} \right)^2 = \frac{17}{18}}  $

$x+\frac{1}{3}  =\pm\sqrt{\frac{17}{18}} }   $

Solving $\sqrt{\frac{17}{18}} $

$\sqrt{\frac{17(18)}{18(18)}}= \sqrt{\frac{306}{324}}=\frac{3\sqrt{34} }{18} =\frac{\sqrt{34} }{6} $

Then,

$x+\frac{1}{3}  =\pm\frac{\sqrt{34} }{6}  $

$x =-\frac{1}{3} \pm\frac{\sqrt{34} }{6}  $

$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

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3 years ago
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Are the two expressions in the equation 2b + 5 + 1b = 3b + 5 equal or equivalent? How do you know
vodka [1.7K]

Given:

The expression is

2b+5+1b=3b+5

To find:

Whether the two expression in the equation are equal or equivalent.

Solution:

If two expression are exactly the same, then they are equal and if the two expressions are different but the after simplification both are same, then they are called equivalent expressions.

We have,

2b+5+1b=3b+5

Taking LHS, we get

LHS=2b+5+1b

On combining liker terms, we get

LHS=(2b+1b)+5

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In the given equation both expression are different but after simplification LHS = RHS, therefore the expression are equivalent not equal.

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$350 increased by 42%
irina [24]

Answer:

497

Step-by-step explanation:

350*1.42

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