Memorize that molarity = moles/liters and you can get these
1) Calculate the number of moles of Cu SO4 . 5H20 by dividing the specified mass by the molar mass.
2) The ratio of production given by the equation is 1 mol of Cu SO4 . 5 H2O to 1 mol of Cu SO4=> 1:1, meaning that the number of moles of Cu SO4 produced is the same number of moles of Cu SO4.5H20 heated.
3) Finally mutiply the number of moles of Cu SO4 by its molar mass and there you have the mass of Cu SO4 produced.
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Answer:
1) 0.0625 g.
2) 0.0125 g.
Explanation:
<em>1) A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution?</em>
mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.
mass% of NaOH = 25.0%, mass of NaOH = ??? g, mass of solution = 0.250 g.
∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (25.0%)(0.250 g)/100 = 0.0625 g.
<em>2) What mass of NaOH must be added to the solution to increase the concentration to 30.00% by mass?</em>
We can use the relation:
mass% of NaOH = [(mass of NaOH)/(mass of solution)] x 100.
mass% of NaOH = 30.0%, mass of NaOH = ??? g, mass of solution = 0.250 g.
∴ mass of NaOH = (mass% of NaOH)(mass of solution)/100 = (30.0%)(0.250 g)/100 = 0.075 g.
∴ The mass of NaOH should be added = 0.075 - 0.0625 = 0.0125 g.
Answer:
Os óxidos são compostos binários formados pela reação do oxigênio com outros elementos. O oxigênio é altamente reativo por natureza. Eles reagem com metais e não metais para formar óxidos.
Os óxidos normalmente reagem com ácidos ou bases, às vezes ambos. ... Os metais tendem a formar óxidos básicos, os não metais tendem a formar óxidos ácidos e os óxidos anfotéricos são formados por elementos próximos à fronteira entre metais e não metais (metaloides).
Explanation:
When we assume that our solvent is water with total weight 100 g:
so we need to get the mass of K2SO3:
mass of K2SO3 = moles K2SO3 * Mw of K2SO3
now we need to get first the Mw of K2SO3 = 2*39 + 1*32 + 3*16 = 158 g/mol
by substitution:
∴ mass of K2SO3 = 0.0328 moles * 158 g/mol = 5.18 g
∴the mass of water = 100 g - 5.18 g = 94.8 g
∴ moles of water = mass of water / Mw of water
= 94.8 g / 18 g/mol
= 5.2 moles
∴the total moles = moles of water + moles of K2SO3
= 5.2 + 0.0328 = 5.266 moles
∴ the weight/weight % of K2SO3 = moles of K2SO3 / total moles*100
= 0.0325 moles / 5.266 moles *100
= 0.0062 *100
= 0.62 %