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eduard
3 years ago
9

A car is going 5m/s around a bend with a radius of 10m/s why is the accelerant?

Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

The Answer is 50 m2 / s2

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To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la
ra1l [238]
Force, newtons 3rd law of motion stated for every action there is an equal and opposite reaction
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3 years ago
Feng and Isaac are riding on a merry-ground. Feng rides on a horse at the outer rim of the circular platform, twice as far from
kogti [31]

Answer: The question is incomplete or missing details. here is the remaining part of the question ;

1. impossible to determine

2. half of Isaac’s

3. the same as Isaac’s

4. twice Isaac’s

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Explanation:

Since we have been told that both feng and isaac are riding on a merry go round i.e in a circular motion, irrespective of how fast one ride above the other, the angular speed will be constant since they are riding on a merry go round, as such both feng and isaac will maintain equal angular speed, hence the angular speed of feng will be the same as that of Isaac.

4 0
4 years ago
Plz help me! <br><br> How do electromagnetic fields work?
MrMuchimi

Answer:

Electromagnetic field, a property of space caused by the motion of an electric charge. A stationary charge will produce only an electric field in the surrounding space. If the charge is moving, a magnetic field is also produced. An electric field can be produced also by a changing magnetic field.

5 0
3 years ago
Match each situation
EastWind [94]
A: is potential
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3 years ago
A 235.0 g metal block absorbs 2.44 × 103 J of heat to raise its temperature by 35 K. What is the specific heat of the metal? Sho
andrew-mc [135]
When an object absorbs an amount of energy equal to Q, its temperature raises by \Delta T following the formula
Q=m C_s \Delta T
where m is the mass of the object and C_s is the specific heat capacity of the material.

In our problem, we have Q=2.44 \cdot 10^3 J, m=235.0 g and \Delta T=35 K, so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
C_s =  \frac{Q}{m \Delta T}= \frac{2.44 \cdot 10^3 J}{(235.0 g)(35 K)}=0.297 J g^{-1} K^{-1}
3 0
4 years ago
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