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eduard
3 years ago
9

A car is going 5m/s around a bend with a radius of 10m/s why is the accelerant?

Physics
1 answer:
Elena-2011 [213]3 years ago
3 0

The Answer is 50 m2 / s2

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Mechanical energy that has been ‘lost' to friction isn't really lost. It just is no longer in its mechanical form. True or False
Vadim26 [7]

Answer:

True.

Explanation:

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

Furthermore, the mechanical energy of a physical object or body is the sum of the potential energy and kinetic energy possessed by the object or body.

Mathematically, it is given by the formula;

Mechanical energy = G.P.E + K.E

Mechanical energy that has been ‘lost' to friction isn't really lost. It just is no longer in its mechanical form. This is ultimately in accordance with the law of conservation of energy, which states that energy cannot be destroyed but can only be converted or transformed from one form to another.

Hence, Mechanical energy that has been ‘lost' to friction isn't really lost but converted into heat energy.

4 0
3 years ago
The tonga trench in the pacific ocean is 36,000 feet deep. assuming that sea water has an average density of 1.04 g/cm3, calcula
MakcuM [25]
1110 atm    

Let's start by calculating how many cm deep is 36,000 feet. 

 36000 ft * 12 in/ft * 2.54 cm/in = 1097280 cm   

 Now calculate how much a column of water 1 cm square and that tall would mass. 

 1097280 cm * 1.04 g/cm^3 = 1141171.2 g/cm^2   

 We now have a number using g/cm^2 as it's unit and we desire a unit of Pascals ( kg/(m*s^2) ).  

 It's pretty obvious how to convert from g to kg. But going from cm^2 to m is problematical. Additionally, the s^2 value is also a problem since nothing in the value has seconds as an unit. This indicates that a value has been omitted. We need something with a s^2 term and an additional length term. And what pops into mind is gravitational acceleration which is m/s^2. So let's multiply that in after getting that cm^2 term into m^2 and the g term into kg.   

 1141171.2 g/cm^2 / 1000 g/kg * 100 cm/m * 100 cm/m = 11411712 kg/m^2 

 11411712 kg/m^2 * 9.8 m/s^2 = 111834777.6 kg/(m*s^2) = 111834777.6 Pascals   

 Now to convert to atm 

 111834777.6 Pa / 1.01x10^5 Pa/atm = 1107.2750 atm   

 Now we gotta add in the 1 atm that the atmosphere actually provides (but if you look closely, you'll realize that it won't affect the final result). 

 1107.274 atm + 1 atm = 1108.274 atm   

 And finally, round to 3 significant figures since that's the accuracy of our data, giving 1110 atm.
8 0
3 years ago
give three examples from the device on the apply page where potential energy was converted to kinetic energy
Elodia [21]

a water turbine drops water onto a blade which gains ke at water's gpe expense

4 0
3 years ago
A ball is thrown downward from the top of a building with an initial speed of 25 m/s.
Bumek [7]

Answer:

h = 69.6 m

Explanation:

Data:

  • Vo = 25 m/s
  • t = 2.0 s
  • g = 9.8 m/s²
  • h = ?

Formula:

  • \boxed{\bold{h=V_{0}*t+\frac{g*(t)^{2}}{2}}}

Replace and solve:

  • \boxed{\bold{h=25\frac{m}{s}*2.0\ s+\frac{9.8\frac{m}{s^{2}}*(2.0\ s)^{2}}{2}}}
  • \boxed{\bold{h=50\frac{m}{s^{2}}+\frac{9.8\frac{m}{s^{2}}*4\ s^{2}}{2}}}
  • \boxed{\bold{h=50\ m+\frac{39.2\ m}{2}}}
  • \boxed{\bold{h=50\ m+19.6\ m}}
  • \boxed{\boxed{\bold{h=69.6\ m}}}

The building has a height of <u>69.6 meters.</u>

Greetings.

5 0
3 years ago
A motor spins up the flywheel with a constant torque of 50 n⋅m. how long does it take the flywheel to reach top speed?
dimulka [17.4K]

A motor spins upward the flywheel with a persistent torque of 50N⋅m.

What time does it take the flywheel to get to the top speed?
From the equation: 
Tj = J*dω/dt 


you can get the two equations: 
Δt1= J1*Δω/Tj = 240*125.66/50 = 603.17 sec 
Δt2= J2*Δω/Tj = 120*125.66/50 = 301.58 sec 

6 0
4 years ago
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