1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reptile [31]
3 years ago
7

Items Item 3 How much force is needed to cause a 15 kilogram bicycle to accelerate at a rate of 10 meters per second per second?

10 newtons 150 newtons 1.5 newtons 15 newtons
Physics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0

Net force = (mass) x (acceleration) . . . . that's Newton's 2nd law of motion

Net force = (15 kg) x (10 m/s²)

<em>Net force = 150 Newtons</em>

You might be interested in
What is a normal resting heart rate for adults, according to the American
kicyunya [14]
The answer of this question is
No B
7 0
3 years ago
El peso normal de un estudiante de secundaria es 725 N y el área de los dos zapatos que usa es de 412 cm2 . La presión medida qu
kotykmax [81]

Answer:

Presión = 175,97 N/m²

Explanation:

Dados los siguientes datos;

Peso del alumno (fuerza) = 725N

Área de zapatos = 412 cm² a metros cuadrados = 412/100 = 4.12 metros

Para encontrar la presión, usaríamos la siguiente fórmula;

Presión = fuerza / área

Presión = 725 / 4.12

Presión = 175,97 N/m²

8 0
3 years ago
A 70-cm-diameter wheel accelerates uniformly from 160rpm to 280rpm in 4.0s. Determine (a) its angular acceleration, and (b) the
poizon [28]

Explanation:

Given that,

Diameter of the wheel, d = 70 cm = 0.7 m

Initial angular speed, \omega_i=160\ rpm=16.75\ rad/s

Final angular speed, \omega_f=280\ rpm=29.32\ rad/s

Time, t = 4 s

(a) Angular acceleration,

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{29.32-16.75}{4}\\\\\alpha =3.14\ rad/s^2

(b) Tangential acceleration is :

a=r\alpha \\\\a=0.35\times 3.14\\\\a=1.085\ m/s^2  

Angular speed of the wheel after 2 seconds is :

\omega_f=\omega_i+\alpha t\\\\\omega_f=16.75+3.14\times 2\\\\\omega_f=23.03\ rad/s

Radial acceleration will be :

a=\omega_f^2r\\\\a=(23.03)^2\times 0.35\\\\a=185.6\ m/s^2

Hence, this is the required solution.

4 0
3 years ago
Doe anyone get this ​
8_murik_8 [283]

Answer:

we know a = F/ M

Explanation:

  • 2 m/s²
  • 0.19 m/s²
  • 9.25 m/ s²
  • 0.04 m/s²
  • 100.39 m/s²

4 0
3 years ago
9 The friction between the car and the mud is equivalent to the__________________.
kakasveta [241]
Answer: e. None

Explanation: when the car goes into the muddy area, then the friction force on the tire is too small so the wheels are turned and slipped. Friction in this case is beneficial
5 0
3 years ago
Other questions:
  • What are the applications of newton law of gravitation
    12·1 answer
  • You ride your bike for 1.5 h at an average velocity of 8 km/h, then for 30 min at 19 km/h. what is your average velocity?
    5·1 answer
  • Lindsey wants to know if mineral water will make sunflowers grow taller than plain water. In Group A, she pours one cup of miner
    13·1 answer
  • During a gust of wind, the blades of the windmill are given an angular acceleration of α=(0.2 θ) rad/s2, where θ is measured in
    15·1 answer
  • A runner covers onelap of a circular track 40.0m in diameter in 64.0s .
    11·1 answer
  • a box having a mass of 50 kg is dragged across a horizontal floor by means of a rope tied on the front of it. the coefficient of
    12·1 answer
  • What conditions are needed for germination? Air, water, and warmth Cold air, water, and soil Water, warmth, and a good location
    11·2 answers
  • A gold ball has a mass of 45g. In a speed test, a golf ball was driven from rest to a velocity of 90m/s.
    12·1 answer
  • How old is the earth? PLEASE HELP ME WITH THIS QUESTION BANANAFANART
    10·1 answer
  • 3.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!