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JulsSmile [24]
3 years ago
6

The atmosphere of Venus contains carbon dioxide and nitrogen gases. At the planet’s surface, the temperature is about 730 K, the

total atmospheric pressure is 98 atm, and the partial pressure of carbon dioxide is 94 atm. If scientists wanted to collect 10.0 moles of gas from the surface of Venus, what volume of gas should they collect?
Physics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

volume of gas is  6.10 L

Explanation:

Given data

temperature = 730 K

pressure = 98 atm

pressure = 94 atm

gas  = 10 moles

to find out

volume of gas

solution

we will apply here formula that is

PV = n RT

here P = 98 , n =10 ,  R = 0.082 and T = 730

put all these value we get Volume v

Volume = 10 (0.082) 730 / 98

volume = 598.6 / 98

volume = 6.108163265

so volume of gas is  6.10 L

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Given the frequency of an electromagnetic wave, what else can you find immediately?
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Answer:

wavelength

Explanation:

An electromagnetic waves is produced due to interaction of oscillating electric and magnetic field when they interacts perpendicular to each other. For example, Gamma rays, X rays , ultraviolet rays, visible radiations, infrared rays, micro waves, radio waves.

All the electromagnetic waves have velocity equal to velocity of light.

If the frequency of electromagnetic wave is unknown then we find the wavelength of wave. the formula used is

Wave speed = wavelength x frequency

3 0
3 years ago
The boiling point of water at sea level is 100 °c. at higher altitudes, the boiling point of water will be
Scilla [17]
   <span> The boiling point of water at sea level is 100 °C. At higher altitudes, the boiling point of water will be.....
a) higher, because the altitude is greater.
b) lower, because temperatures are lower.
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8 0
2 years ago
A 1.5m long string weighs 0.0020 kg. It is tensioned to 100N. A disturbance travels along it with a wavelength of 1.5m, find:a)
Zigmanuir [339]

Answer:

the propagation velocity of the wave is 274.2 m/s

Explanation:

Given;

length of the string, L = 1.5 m

mass of the string, m = 0.002 kg

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wavelength, λ = 1.5 m

The propagation velocity of the wave is calculated as;

v = \sqrt{\frac{T}{\mu} } \\\\\mu \ is \ mass \ per \ unit \ length \ of \ the \ string\\\\\mu = \frac{0.002 \ kg}{1.5 \ m} = 0.00133 \ kg/m\\\\v = \sqrt{\frac{100}{0.00133} } \\\\v = 274.2 \ m/s

Therefore, the propagation velocity of the wave is 274.2 m/s

7 0
2 years ago
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olga2289 [7]

Answer:

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Explanation:

7 0
2 years ago
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The answer is the first one
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3 years ago
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