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JulsSmile [24]
3 years ago
6

The atmosphere of Venus contains carbon dioxide and nitrogen gases. At the planet’s surface, the temperature is about 730 K, the

total atmospheric pressure is 98 atm, and the partial pressure of carbon dioxide is 94 atm. If scientists wanted to collect 10.0 moles of gas from the surface of Venus, what volume of gas should they collect?
Physics
1 answer:
balu736 [363]3 years ago
4 0

Answer:

volume of gas is  6.10 L

Explanation:

Given data

temperature = 730 K

pressure = 98 atm

pressure = 94 atm

gas  = 10 moles

to find out

volume of gas

solution

we will apply here formula that is

PV = n RT

here P = 98 , n =10 ,  R = 0.082 and T = 730

put all these value we get Volume v

Volume = 10 (0.082) 730 / 98

volume = 598.6 / 98

volume = 6.108163265

so volume of gas is  6.10 L

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Answer:

Explanation:

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net force = mass x acceleration = m x 0 = 0

Now frictional force = μ mg where μ is coefficient of kinetic friction

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3 years ago
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Maksim231197 [3]

Answer:

If the frequency of the motion of a simple harmonic oscillator is doubled , then maximum speed of the oscillator changes by the factor 2

Explanation:

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6 0
3 years ago
Suppose the half-life of an element is 10 years. How many half-lives will it take before only about 6% of the original sample re
sergiy2304 [10]
You don't need to worry about the 10 year bit with this question. Just grab a calculator and divide 100/2, then the answer to that (50) by 2 etc and keep dividing by 2 until you get down to 6.25.

The answer ends up being 4 half lives :)

If you don't understand what a half life is please let me know :)
4 0
3 years ago
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While running around the track at school, Milt notices that he runs due East on the 100m homestretch and due West on the 100m ba
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Answer a would be correct since velocity is a vector and has a magnitude and a direction. In this case v₁ = - v₂.
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Use Eq. cosϕ=R/Z to show that the average power delivered by the source in an L−R−C series circuit is given by Pav = I^2rmsR .
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Answer:

Explanation:

In a L C R circuit, the average power is given by

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