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3 years ago

Pancake syrup taken out of the refrigerator will be difficult to pour because low temperature increases viscosity.

2 answers:

8 0

The answer would be A. True. This is because of friction. <span>Liquids, have friction, too, not just against solids (for example, water against a drinking glass)—but also internal friction, the liquid against itself. This internal friction is called viscosity. Different liquids have different viscosities, which means some liquids flow more easily than others. You will notice this if you think about squirting water out of a bottle or squirt gun. Imagine how much harder that would be to do with cold syrup! I hope this helped! </span>

DiKsa [7]3 years ago

4 0

<span>Pancake syrup taken out of the refrigerator will be difficult to pour because low temperature increases viscosity.

a)True

</span>

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Bob and John are pulling in different directions. If Bob is pulling to the right with a force of 10N, and John is pulling to the

Murljashka [212]

Answer:

The net force on the box is 2 N to the left.

The box will move to the left.

The acceleration on the box is 0.5 m/s^2 to the left.

Explanation:

Let's say movement to the right is positive and left is negative.

Bob: +10 N

John: -12 N

Add those together and you get a net force of -2 N, and the negative sign means that the box is moving to the left.

For the acceleration:

Fnet = ma

-2 = (4 kg)a

a = -0.5 m/s^2

Again, the negative sign in this answer means the box is being accelerated to the left.

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3 years ago

Covalent bonds tend to make atoms more stable by helping them

Lelechka [254]

Achieve a full outer shell

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2 years ago

The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m

Julli [10]

Answer:

$v=(6ti+6k)\ m/s$

Explanation:

Given that,

The position of a particle is given by :

$r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m$

Let us assume we need to find its velocity.

We know that,

$v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s$

So, the velocity of the particle is $(6ti+6k)\ m/s$ .

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3 years ago

What’s an example of contact friction

kotegsom [21]

Answer:

a nightstand on a lamp table

Explanation:

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3 years ago

The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be

Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>

It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
Mathematically, T²∝a³

<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>

The time period of geosynchronous orbit is 24 hours or 1440 minutes.
As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
a1= (T1/T2)⅔×a2

= (1440/90)⅔×6780

= 43,090 km

Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

brainly.com/question/16705471

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1 year ago