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aalyn [17]
3 years ago
8

Number of molecules in 16 grams of h2co3

Chemistry
2 answers:
enyata [817]3 years ago
8 0

For this one u can work out the amount of moles in h2co3 by using moles=mass/mr(of h2co3 is 52)

so 16/62=0.258moles then u use the equation

number of particle = moles × 6.02×10^23

=0.258×6.02 ×10^23

=1.55×10^23 molecules.

hope this helps

umka2103 [35]3 years ago
4 0
1 mole =6.023×10 root 23. 16 x 10root 23=160root 23 mole.
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Considering the ideal gas law, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

<h3>Definition of ideal gas</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

<h3>Ideal gas law</h3>

An ideal gas is characterized by absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

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<h3>Volume of gas</h3>

In this case, you know:

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  • V= ?
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  • R= 0.082 \frac{atmL}{molK}
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Replacing in the ideal gas law:

1.50 atm×V = 11.36 moles×0.082\frac{atmL}{molK} × 298 K

Solving:

V= (11.36 moles×0.082\frac{atmL}{molK} × 298 K) ÷ 1.50 atm

<u><em>V= 184.899 L</em></u>

Finally, the volume of gas produced at 25.0 °C and 1.50 atm is 184.899 L.

Learn more about the ideal gas law:

<u>brainly.com/question/4147359?referrer=searchResults</u>

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