Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

or,
..........(1)
where,
= rate of effusion of nitrogen gas = 
= rate of effusion of sulfur dioxide gas = ?
= molar mass of nitrogen gas = 28 g/mole
= molar mass of sulfur dioxide gas = 64 g/mole
Now put all the given values in the above formula 1, we get:


Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.
Answer:
carbon dioxide
Explanation:
carbon dioxide is the primary greenhouse gas produced by burning fossil fuels like coal and oil
Answer
let the oxidation of sulphur is x
2(+1)+x+4(-2)=0
+2+x-8=0
+2-8+x=0
-6+x=0
x=6
Explanation:
i hope this will help you:)
Answer:
C. water acts as a radiation shield to reduce the radiation level