True or false. A bond between a metal atom and a nonmetal atom is likely an iconic bond
1 answer:
You might be interested in
Answer:
a) 72 °F= 22.22 °C
b) 213.8 °C= 416.84°F
c) 180 °C= 453.15 °K
d) 315 °K= 107.33 °F
e) 1750 °F= 1227.594 °K
f) 0 °K= -459.67 °F
Explanation:
Para realizar el intercambio de unidades debes tener en cuenta las siguientes conversiones:
- Fahrenheit a Celsius:
- Celsius a Fahrenheit: °F= °C*1.8 + 32
- Celsius a Kelvin: °K= °C + 273.15
- Kelvin a Fahrenheit: F= (K -273.15)*1.8 + 32
- Fahrenheit a Kelvin:
Entonces se obtiene:
a) 72 °F= =22.22 °C
b) 213.8 °C= 213.8*1.8 + 32= 416.84°F
c) 180 °C= 180°C + 273.15= 453.15 °K
d) 315 °K= (315 -273.15)*1.8 + 32= 107.33 °F
e) 1750 °F= = 1227.594 °K
f) 0 °K= (0 -273.15)*1.8 + 32= -459.67 °F
<em>Mixed molarity = 0.25 M</em>
<em>Osmotic pressure solution: 6.15 atm</em>
<h3><em>Further explanation</em></h3>Osmotic pressure is the minimum pressure given to the solution so that there is no osmotic displacement from a more dilute solution to a more concentrated solution.
General formula:
π = osmotic pressure (atm)
M = solution concentration (mol / l)
R = constant = 0.08205 L atm mol-1 K-1
T = Temperature (Kelvin)
Mixing solution
To find the molarity of the mixed solution we can use the following formula:
Vc. Mc = V1.M1 + V2.M2
where
Mc =Mixed molarity
Vc = mixed volume
Mr. NaCl = 58.5
Mr. Dextrose = C₆H₁₂O₆ = 180
mole NaCl = gram / Mr
mole NaCl = 1.75 / 58.5 = 0.03
Dextrose mole = 40/180 = 0.22
Assuming 1 liter of solution
M mixture = mole NaCl + mole dextrose / 1 liter
M mixture = 0.03 + 0.22 / 1 L
M mix = 0.25 M
T = 25 + 273 = 298 K
The osmosis pressure of the solution becomes:
π = 0.25. 0.0825. 298 = 6.15 atm
<h3><em>Learn more</em></h3>The osmotic pressure brainly.com/question/8195553
<h3><em>Answer details </em></h3>Grade: Senior High School
Subject: Chemistry
Chapter: Colligative property
Keywords: osmotic pressure, molarity, mole,dextrose, NaCl