Answer:
Change in Kinetic Energy is
Solution:
As per the question:
Mass of space craft,
Mass of the sun, M =
Radius of the orbit, R =
Radius of smaller orbit around the sun, r =
Now,
We know that the Gravitational Potential Energy is given by:
where
G = Gravitational constant
r = distance of the space craft from the center of the sun
Now,
Initial Gravitational Potential Energy is:
Now,
Final Gravitational Potential Energy is:
Change in the Gravitational Potential Energy equals the change in the kinetic energy of the space craft.
Thus
Answer:Force on -7 uC charge due to charge placed at x = - 10cm
now we will have
towards left
similarly force due to -5 uC charge placed at x = 6 cm
now we will have
towards left
Now net force on 7 uC charge is given as
towards left
Explanation:
Explanation:
Amount of heat supplied (Q) = 24500 J
Mass (m) = 2 kg
Initial temperature (t1) = 20 ° C
Final temperature (t2) = 35 ° C
Difference in temperature (dt) = t2 - t1 = ( 35 - 20) °C = 15 ° C
Now Specific heat capacity (S) = ?
We know we have the formula;
Q = m * s * dt
24500 = 2 * s * 15
24500 = 30 S
S = 24500 / 30
S = 816.67 J / Kg ° C
The specific heat capacity is 816.67 J/kg°C.
Hope it will help :)
Answer:
The answer is below
Explanation:
The acceleration of a ball rolling down an inclined plane would be greater than that of the acceleration of a ball rolling up if acted upon by a force of equal magnitude. For a ball rolling down an inclined plane, the acceleration due to gravity (gsinθ) acts in the direction of motion of the ball thereby leading to an increase in the acceleration of the ball; while for a balling rolling upwards, the acceleration due to gravity acts in the direction opposite to the motion of the ball thereby leading to a decrease in the acceleration of the ball.
Answer:
3.44 metres
Explanation:
To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.
Resolving into x - component
- 2.4cos32 + 4.9cos27 = 2.3306
Resolving into y - component
- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553
The vector sum of the displacement will be
Sqrt( 2.3^2 + 2.6^2) =
Sqrt ( 11.81)
3.44 m
Therefore, the vector sum of the displacements is 3.44 metres