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konstantin123 [22]
2 years ago
15

1. A car accelerates uniformly from 12 m/s to 39 m/s in 12 seconds. What is the car's average acceleration

Physics
1 answer:
Alinara [238K]2 years ago
5 0

Answer:

(1) 2.25m/s^2

(2) 45.6m

Explanation:

(1) A car accelerates uniformly from 12m/s to 39m/s in 12 seconds

Therefore the average acceleration can be calculated as follows

a = 39-12/12

a = 27/12

a= 2.25m/s^2

(2) A butterfly is flying at 4m/s , it accelerates uniformly at 1.2 m/s for 6 seconds

u= 4

a= 1.2

t= 6

Therefore the distance can be calculated as follows

S= ut + 1/2at^2

= 4×6 + 1/2 × 1.2 × 6^2

= 24 + 1/2 × 1.2 × 36

= 24 + 1/2 × 43.2

= 24 + 21.6

S = 45.6m

Hence the butterfly travels at 45.6m

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The average speed of the cars is 50mph

Explanation:

Option C

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3 years ago
Alfred Wegener noticed that Africa and South America seem to fit together what part of a scientific method does this correlate w
AlexFokin [52]

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This theory states that the outer rigid layer of the earth or the lithosphere is divided into a couple of dozen "plates" that move around across he earth's surface relative to each other. That is why Alfred Wegener noticed that Africa and South America seem to fit together.

Though Wegener's hypothesis lacked a geological mechanism to explain how the continents could drift across the earth's surface as he proposed.

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2 years ago
An object is projected upward from the surface of the earth with an initial speed of 3.7 km/s. find the maximum height it reache
Mariulka [41]
The kinetic energy of the object just after it starts its motion from the Earth surface is
K= \frac{1}{2}mv^2
where m is the object mass and v=3.7 km/s=3700 m/s its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
U=mgh
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Since the energy of the object must be conserved, K=U, therefore we can write
\frac{1}{2}mv^2 =mgh
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h= \frac{v^2}{2g}= \frac{(3700 m/s)^2}{2\cdot 9.81 m/s^2}=  6.98 \cdot 10^5 m=698 km
5 0
3 years ago
What is the distance magnification formula
damaskus [11]

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3 years ago
An inductor in the form of an air-core solenoid contains 191 turns, is of length 17.9 cm, and has a cross-sectional area of 1.2
Umnica [9.8K]

Answer:

The magnitude of the uniform rate of change in current through the inductor is 13.66 A/s.

Explanation:

To find the magnitude of the uniform rate of change in current through the inductor we will use the formula:

ΔI/Δt = e×l / μ0×N×A

Now, put all the given  values in this formula and then you will get your answer,

ΔI/Δt = 205×10^-6×19.2 / 1.2566×10^-6×191×1.2

ΔI/Δt = 13.66 A/s.

4 0
3 years ago
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