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Snezhnost [94]
3 years ago
5

1. Which of the following elements is a transition metal?

Chemistry
2 answers:
Orlov [11]3 years ago
8 0
Where are the following elements to choose from?
navik [9.2K]3 years ago
3 0

Answer:

Scandium

Titanium

Vanadium

Chromium

Manganese

Iron

Cobalt

Nickel

Copper

Zinc

Yttrium

Zirconium

Niobium

Molybdenum

Technetium

Ruthenium

Rhodium

Palladium

Silver

Cadmium

Hafnium

Tantalum

Tungsten

Rhenium

Osmium

Iridium

Platinum

Gold

Mercury

Rutherfordium

Dubnium

Seaborgium

Bohrium

Hassium

Meitnerium

Ununnilium

Unununium

Ununbium

Are all transition metals

Explanation:

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Seven valence electrons are present in the 'Lewis structure' for the given chlorine atom

A Chlorine atom has total 17 electrons in total. In the 'first orbit' 2 electrons, 10 electrons in the 'second orbit' and finally 7 electrons in the last orbit. As Chlorine is a Group 7 element, chlorine will have 7 'valence electrons' in its outermost orbit. While drawing the 'Lewis structure' of Chlorine we shall put seven dots that is the electrons or valance electrons around the symbol of Chlorine (CI).

<h3>What are Valence electrons ?</h3>

The electrons in an atom's outermost shell, or energy level, are called valence electrons. For instance, the valence electrons of oxygen are six, with two in the 2s subshell and four in the 2p subshell.

  • An atom's outer shell electrons, known as valence electrons, can take role in the creation of chemical bonds. When two atoms establish a single covalent bond, normally both atoms contribute one valence electron to create a shared pair. The ground state of an atom is its state with the least amount of energy.

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D

Explanation:

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Which statement is true about a proton and a neutron?
igor_vitrenko [27]

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The decomposition reaction: SO,Cl, SO2 + Cl2, has a first order rate constant of 2.2 x 10's at 320 °C. If the initial concentrat
trapecia [35]

Answer :

(a) The concentration of SO_2Cl_2 after 1.00 hr will be 0.0037 M

(b) The concentration of SO_2Cl_2 after 1.00 day will be 0.00060 M

Explanation :

(a) The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration of SO_2Cl_2 at time 't'  = ?

[C_o] = concentration of SO_2Cl_2 at time '0' = 0.0040 M

k = rate constant = 2.2\times 10^{-5}s^{-1} (assuming the power of 10 from the correct source)

t = time = 1.00 hr = 3600 s (1 hr = 3600 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.0040)\times e^{-(2.2\times 10^{-5})\times (3600)}

[C_t]=0.0037M

Thus, the concentration of SO_2Cl_2 after 1.00 hr will be 0.0037 M

(b) The expression for first order reaction is:

[C_t]=[C_o]e^{-kt}

where,

[C_t] = concentration of SO_2Cl_2 at time 't'  = ?

[C_o] = concentration of SO_2Cl_2 at time '0' = 0.0040 M

k = rate constant = 2.2\times 10^{-5}s^{-1}

t = time = 1.00 day = 86400 s (1 day = 86400 s)

Now put all the given values in the above expression, we get:

[C_t]=(0.0040)\times e^{-(2.2\times 10^{-5})\times (86400)}

[C_t]=0.00060M

Thus, the concentration of SO_2Cl_2 after 1.00 day will be 0.00060 M

6 0
3 years ago
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