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NeTakaya
3 years ago
14

What is the molality of a solution of 0.35 moles of sucrose in dissolved in

Chemistry
1 answer:
telo118 [61]3 years ago
5 0

Answer:

i Think it is 1.3500

Explanation:

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. how many lone pairs of electrons are present in the lewis structure of calcium sulfide?
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Explanation:
                     Calcium Sulfide is an ionic compound made up of Ca²⁺ and S²⁻.
Ca²⁺ is formed as,

                                   Ca    →    Ca²⁺  +  2 e⁻

These two electrons are accepte by Sulfur as,

                                     S  +  2 e⁻    →    S²⁻

So, before accepting 2 electrons S was having six valence electrons, after accepting two electrons from Ca it has 8 electrons which are present in four pairs as shown below,

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Answer:

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Im not sure I just goggled it

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