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klasskru [66]
3 years ago
10

A 75.0 mL sample of sulfuric acid (H2SO4) is neutralized by 25.0 mL of 0.150 M NaOH. Calculate the molarity of the sulfuric acid

solution.
1. 0.03500 M 2. 0.0500 M 3. 0.450 M 4. 0.0250 M 5. 0.100 M
Chemistry
1 answer:
Juli2301 [7.4K]3 years ago
6 0

Answer:

THE MOLARITY OF SULFURIC ACID SOLUTION IS 0.05 L

Explanation:

Ca Va = Cb Vb

Ca = ?

Va = 75.0mL = 0.075 L

Cb = 0.150 M

Vb = 25.0 mL = 0.025 L

Ca = CbVb/ Va

Ca = 0.150 * 0.025 / 0.075

Ca = 0.00375 / 0.075

Ca = 0.05 M

The molarity is 0.05 L

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Answer:

C

Explanation:

Temperature is directly related to kinetic energy (KE). As we raise temperature, we are raising KE, as well. Particles with more KE move more quickly and with more force.

This means that these particles are more likely to collide with each other and react to allow the chemical reaction to follow through. In turn, if the chemical reaction is more likely to go to completion, the reaction rate increases, eliminating A and B.

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Hope this helps!

4 0
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Answer:

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