Answer:
[CH₃COOH] = 1.70 M
Explanation:
When we talk about concentration we can determine Molarity
Molarity determines the moles of solute that are contained in 1L of solution.
In this case our solute is the acetic acid.
M = mol/L
M = 0.99 mol /0.58L → 1.70 M
We can also make a rule of three
In 0.58 L of solution we have 0.99 moles of solute
In 1 L of solution we may have (1 . 0.99) / 0.58 = 1.70 moles
Acetic acid is a weak acid, partially dissociated in water.
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
