Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. If there is no air resistance, when
1 answer:
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Answer:
<em>2.78m/s²</em>
Explanation:
Complete question:
<em>A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?</em>
According to Newton's second law of motion:
Where:
is the coefficient of friction
g is the acceleration due to gravity
Fm is the moving force acting on the body
Ff is the frictional force
m is the mass of the box
a is the acceleration'
Given
Required
acceleration of the box
Substitute the given parameters into the resulting expression above:
Recall that:
9.8sin30 - 0.25(9.8)cos30 = ax
9.8(0.5) - 0.25(9.8)(0.866) = ax
4.9 - 2.1217 = ax
ax = 2.78m/s²
<em>Hence the acceleration of the box as it slides down the incline is 2.78m/s²</em>
To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volume V , ratio for (c) a parallelepiped of dimensions × 2 a will be
What will be the ratio of surface area and the volume of the parallelepiped
We will proceed by stating the equations of the surface area and the volume of each shape, and then identifying each of the surface area and the volume, we will take their ratios, and as it is asking for the shape which has the minimum surface area to volume ratio, therefore at some given volume, .
The parallelepiped whose dimension is given as
the surface area and the volume is given respectively by:
Let the volume be equal to the constant c, we get:
Hence the ratio is given by:
Calculating the constants, by substituting the value of in (3), we get:
To learn more about parallelepiped, refer to:
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