<span>First we can find the circumference of the whole circle with a radius of 5 feet.
circumference = 2 pi radius
circumference = (2 pi) (5 feet)
circumference = (10 pi) feet
From one high point to the other high point, the string moves through an angle of 10 degrees. Since a full circle is 360 degrees, this angle is 1/36 of a full circle.
Therefore, the arc length is 1/36 of the whole circumference.
arc length = (1/36) (circumference)
arc length = (1/36) (10 pi) feet
arc length = 0.873 feet</span>
Answer:
4.384 * 10^13
Explanation:
Given the expression :
[(6.67 * 10^-11) * (1.99 * 10^30)] ÷ [(1.74*10^3)*(1.74*10^3)]
Applying the laws of indices
[(6.67 * 1.99) *10^(-11 + 30)] ÷ [(1.74 * 1.74) * 10^3+3]
13.2733 * 10^19 ÷ 3.0276 * 10^6
(13.2733 / 3.0276) * 10^(19 - 6)
4.3840996 * 10^13
= 4.384 * 10^13
Answer:
a. 20m/s
b.50N
c. Turkey has a larger mass than the ball. Neglible final acceleration and therefore remains stationery.
Explanation:
a. Given the force as 50N, times as 0.2seconds and the weight of the ball as 0.5 kg, it's final velocity can be calculated as:
![F\bigtriangleup t=m\bigtriangleup v\\\\50N\times 0.2s=0.5kg\times \bigtriangleup v\\\\\bigtriangleup v=2(50N\times0.2)\\\\=20m/s](https://tex.z-dn.net/?f=F%5Cbigtriangleup%20t%3Dm%5Cbigtriangleup%20v%5C%5C%5C%5C50N%5Ctimes%200.2s%3D0.5kg%5Ctimes%20%5Cbigtriangleup%20v%5C%5C%5C%5C%5Cbigtriangleup%20v%3D2%2850N%5Ctimes0.2%29%5C%5C%5C%5C%3D20m%2Fs)
Hence, the velocity of the ball after the kick is 20m/s
b.The force felt by the turkey:
#Applying Newton's 3rd Law of motion, opposite and equal reaction:
-The turkey felt a force of 50N but in the opposite direction to the same force felt by the ball.
c. Using the law of momentum conservation:
-Due to ther external forces exerted on the turkey, it remains stationery.
-The turkey has a larger mass than the ball. It will therefore have a negligible acceleration if any and thus remains stationery.
-Momentum is not conserved due to these external forces.