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r-ruslan [8.4K]
3 years ago
5

Which technique is best for manual in-line stabilization of a person floating faceup on the surface?

Physics
2 answers:
zmey [24]3 years ago
7 0

Answer:

vise grip

Explanation:

Manual in-line stabilization (MILS) of the cervical spine is a type of airway management when dealing with  patients in traumatic condition ..it is a means that is performed by grasping the mastoid process of the patient, so as to prevent the movement of the cervical column during intubation of the trachea

MLS provides a means of stability to the cervical column for a patient in trauma. During this technique, a patient is restricted from moving his or her cervical collar. The vise grip can be used for a patient with neck injury. The technique is used to roll a patient to face up to prevent further injuries.

Elodia [21]3 years ago
7 0

Answer: the technique which is best for manual in-line stabilization of a person floating faceup on the surface is vice grip.

Explanation:

Vice grip is a rescue technique used to prevent further injury to a guest who is suspected of having suffered a spinal injury as the typical posture is floating faceup on the surface.

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Define the term “force”.
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Energy that is applied to an object.

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Define torque qualitatively and quantitatively.
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When you use a wrench to tighten or loosen a nut on a bolt, you are applying torque. It is measured in units of force times distance.  A force of F newtons pulling on a handle of L meters in length would supply a torque of F L newton-meters. More technically, torque is the vector cross product of force times perpendicular distance from the object, F x r = F r sin @
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These are intense, rotating convectional systems that develop over warm ocean areas in the tropics and subtropics, primarily dur
asambeis [7]

Answer:

True.

Explanation:

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4 0
3 years ago
What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic
Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, \dfrac{dB}{dt}=3\ T/s

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

E=N\dfrac{d\phi}{dt}

E=N\dfrac{d(BA)}{dt}

Since, E = IR

IR=NA\dfrac{dB}{dt}

A=\dfrac{IR}{N.\dfrac{dB}{dt}}

A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}

A=0.188\ m^2

or

A=0.19\ m^2

Area of circular cross section is, A=\pi r^2

r=\sqrt{\dfrac{A}{\pi}}

r=\sqrt{\dfrac{0.19}{\pi}}

r = 0.24 m

So, the  radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0
3 years ago
5. a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m. Calculate
omeli [17]

Answer:

<h3>The answer is 2 s</h3>

Explanation:

The time of flight can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance covered

v is the velocity

From the question we have

t =  \frac{100}{50}  =  \frac{10}{5}  \\

We have the final answer as

<h3>2 s</h3>

Hope this helps you

8 0
3 years ago
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