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3 years ago

The mass of an object changes as the distance from the center of gravity changes.

Physics

1 answer:

Alchen [17]3 years ago

8 0

Answer:

true

Explanation:

this is the answer to this question

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Is horsepower the only thing to be considered when purchasing a piece of equipment?Explain.

Novosadov [1.4K]

Answer:

Mostly yes

Explanation:

But you should consider,brand value, material used and lasting of the equipment also

1HP=720W

HP stands for horsepower

It's mostly used in pumps

8 0

2 years ago

Read 2 more answers

) The angular acceleration of the disk is defined by ???? = 3t 2 + 12 rad/s, where t is in seconds. If the disk is originally ro

pshichka [43]

Answer:

a) $\theta = 52\,rad$ , b) $v_{A} = 44\cdot r \,\frac{m}{s}$ , c) $a_{A,n} = 1936\cdot r\,\frac{m}{s^{2}}$ , $a_{A,t} = 24\cdot r\,\frac{m}{s^{2}}$

Explanation:

a) The angular motion is obtained by integrating the angular acceleration function twice:

$\alpha = 3\cdot t^{2} + 12$

$\omega = t^{3} + 12\cdot t + 12$

$\theta = \frac{1}{4}\cdot t^{4} + 6\cdot t^{2} + 12\cdot t$

The angular motion when t = 2 s. is:

$\theta = \frac{1}{4}\cdot (2\,s)^{4} + 6\cdot (2\,s)^{2} + 12\cdot (2\,s)$

$\theta = 52\,rad$

b) Let be $r$ the distance between A and the rotation axis, measured in meters. The magnitude of the angular velocity when t = 2 s. is:

$\omega = (2\,s)^{3} + 12\cdot (2\,s) + 12$

$\omega = 44\,\frac{rad}{s}$

Finally, the magnitude of the velocity is:

$v_{A} = 44\cdot r \,\frac{m}{s}$

c) The angular acceleration of the disk when t = 2 s. is:

$\alpha = 3\cdot (2\,s)^{2} + 12$

$\alpha = 24\,\frac{rad}{s^{2}}$

Lastly, the normal and tangential components at point A are, respectively:

$a_{A,n} = \omega^{2}\cdot r$

$a_{A,n} = \left(44\right)^{2}\cdot r$

$a_{A,n} = 1936\cdot r\,\frac{m}{s^{2}}$

$a_{A,t} = \alpha \cdot r$

$a_{A,t} = 24\cdot r\,\frac{m}{s^{2}}$

6 0

3 years ago

. What is the height in meters of a 5'4" person?

Illusion [34]

Answer:

1.62 meters

Explanation:

For an approximate result, divide the feet (height) by 3.3 to get your approximate meters (height).

5 0

3 years ago

The temperature of a substance during an experiment can be modeled by the function f(x)=−7.5cos(πx30)+31.4 , where f(x) is the t

vekshin1

38.9 degrees celsius

6 0

3 years ago

Read 2 more answers

At what net rate does heat radiate from a 300-m^2 black roof on a night when the roof's temperature is 33.0°C and the surroundin

Fynjy0 [20]

Answer:

24445.85 J/s

Explanation:

Area, A = 300 m^2

T = 33° C = 33 + 273 = 306 k

To = 18° C = 18 + 273 = 291 k

emissivity, e = 0.9

Use the Stefan's Boltzman law

$E = \sigma \times e \times A\times\left ( T^4 -T_{0}^{4}\right )$

Where, e be the energy radiated per unit time, σ be the Stefan's constant, e be the emissivity, T be the temperature of the body and To be the absolute temperature of surroundings.

The value of Stefan's constant, σ = 5.67 x 10^-8 W/m^2k^4

By substituting the values

$E = 5.64 \times 10^{-8}\times 0.9 \times 300 \times (306^{4}-291^{4})$

E = 24445.85 J/s

7 0

4 years ago