Question

"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form. Express your answer as two numbers separated by a comma. Be careful with your signs"

Answer 1

Complete Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.

Express your answer as two numbers separated by a comma. Be careful with your signs.

Answer:

The value is  $dT = ( -0.3, 0.8)$

Explanation:

From the question we are told that

   The first displacement is  $dN = 0.900 \ due \ North$ i.e positive  y-axis

   The  second displacement is  $dW = 0.300 \ miles \ due \ west$ i.e negative  x-axis

   The final displacement is  $dS = 0.100 \ miles \ due \ south$ i.e  negative  y-axis

Generally dW in component for is  

      $dW = (-0.3 , 0)$  

Generally the  total displacement of the student is mathematically represented as

     $dT = ( -0.3, (0.90 - 0.10))$

      $dT = ( -0.3, 0.8)$