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Rudik [331]
3 years ago
6

Plates move mainly due to

Physics
1 answer:
Korvikt [17]3 years ago
5 0

Answer:

Earth Rotation

Explanation:

Earth Rotation seems like the answer

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Jo wants to find out about floating and sinking. She puts a rubber duck and a bar of soap in a
maks197457 [2]

Answer:

the soap sinks because it is more dense than the duck.

7 0
3 years ago
A 12-kg piece of metal displaces 1.6 L of water when submerged. Part A Find its density. Express your answer to two significant
Tatiana [17]

Answer:

ρ = 7500 kg/m³

Explanation:

Given that

mass ,m = 12 kg

Displace volume ,V= 1.6 L

We know that

1000 m ³ = 1 L

Therefore V= 0.0016 m ³

When metal piece is fully submerged

We know that

mass = Density x volume

m=\rho \times V

Now by putting the values in the above equation

\rho=\dfrac{12}{0.0016}\ kg/m^3

ρ = 7500 kg/m³

Therefore the density of the metal piece will be  7500 kg/m³.

6 0
3 years ago
How does the generator effect work?​
notsponge [240]

Answer:

The changing magnetic field within the loops of wire creates an electric field that pushes the electrons in the wire through the lamp, briefly lighting it

Explanation:

The GE demonstrates that a voltage, and hence a current, can be generated by plunging a coil of wire into and out of a strong magnet.

7 0
3 years ago
Total these measurements. Your answer should indicate the proper accuracy. Be sure to include the units in your answer. (Remembe
vivado [14]

Answer:

10

Explanation:

This is tough. The last number  0.2 has only one significant figure. So while the sum of all the numbers is 12.3, you must only leave one sig figure. Rounding to the tenths gives 10.  

3 0
3 years ago
At a distance of 11 cm from a presumably isotropic, radioactive source, a pair of students measure 65 cps (cps = counts per seco
Alborosie

To solve the problem, it is necessary the concepts related to the definition of area in a sphere, and the proportionality of the counts per second between the two distances.

The area with a certain radius and the number of counts per second is proportional to another with a greater or lesser radius, in other words,

A_1*m=M*A_2

A_i =Area

M,m = Counts per second

Our radios are given by

r_1 = 11cm

R_2 = 20cm

m = 65cps

Therefore replacing we have that,

A_1*m=M*A_2

4\pi r_1^2*m = M * 4\pi R_2^2 M

r^2*m=MR^2

M = \frac{m*r^2}{R^2}

M = \frac{65*11^2}{20^2}

M = 19.6625cps

Therefore the number of counts expect at a distance of 20 cm is 19.66cps

7 0
3 years ago
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