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Helga [31]
3 years ago
8

An electron in an atom moves from the ground state to an excited state when the energy of the electron

Chemistry
2 answers:
FromTheMoon [43]3 years ago
8 0

<em>An electron in an atom moves from a ground state to an excited state when the electron energy </em><em>increases </em>

<h2>Further Explanation </h2>

Excitation in physics is the addition of a number of discrete energies (called excitation energies) to a system — such as the nucleus of an atom, atom, or molecule — so as to produce a change, usually from the lowest energy state (ground state) to one of the higher energies (excited state).

In nuclear, atomic and molecular systems, excited states do not continue to be distributed but instead have certain discrete energy values. Thus, external energy (excitation energy) can be absorbed in discrete quantities.

Excitation energy is stored in excited atoms and the nucleus that emits light is usually seen from atoms and as gamma radiation from the nucleus because they return to the ground state. This energy can also be lost by collisions.

In the nucleus, energy is absorbed by protons and neutrons which are transferred to an excited state. Within a molecule, energy is absorbed not only by electrons, which are very enthusiastic for higher energy levels but also by whole molecules, which are highly excited for the discrete states of vibration and rotation.

Learn More

Electron moves brainly.com/question/496960

Excitation brainly.com/question/496960

Details

Class: High School

Subject: Chemistry

Keywords: electron, excitation, energies

NISA [10]3 years ago
7 0
The answer is (2) increases. The definition of excited state is that the electrons have higher energy than ground state. For comprehension, the excited state is ready for reaction so it has higher energy.
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Which postulate of Dalton's atomic theory is the result of the law of conservation of mass
creativ13 [48]

The postulate of Dalton's atomic theory which is a result of the law of conservation of mass is: Atoms are indivisible particles, which can neither be created nor destroyed in a chemical reaction.

8 0
4 years ago
Calculate the percent ionic, the percent covalent, and the bond length (in picometers) of a chemical bond between phosphorus and
kirza4 [7]

Answer:

The correct option is;

4 percent ionic, 96 percent covalent, 222 pm

Explanation:

The parameters given are;

Phosphorus:

Atomic radius = 109 pm

Covalent radius = 106 pm

Ionic radius = 212 pm

Electronegativity of phosphorus = 2.19  

Selenium:

Atomic radius = 122 pm

Covalent radius = 116 pm

Ionic radius = 198 pm

Electronegativity of selenium= 2.55  

The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;

Using Pauling's alternative electronegativity difference method, we have;

\% \, Ionic \ Character = \left [18\times (\bigtriangleup E.N.)^{1.4}  \right ] \%

Where:

Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36

Therefore;

\% \, Ionic \ Character = \left [18\times (0.36)^{1.4}  \right ] \% = 4.3 \%

Hence the percentage ionic character = 4.3% ≈ 4%

the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%

The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;

The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.

The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.

4 0
4 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
choli [55]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
3 years ago
What will be produced at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2
natita [175]

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

6 0
3 years ago
Which nuclear decay emission has the weakest penetrating power?
Romashka [77]
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3 0
3 years ago
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