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blondinia [14]
3 years ago
7

Solve using the quadratic formula

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

Solve the equation for  s  by finding  a  ,  b  , and  c  of the quadratic then applying the quadratic formula.  

s = − 2

Double roots

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The Gonzales family has three children. On summer break they went to an amusement park they bought 3 child tickets for 18.50 and
sergiy2304 [10]

Answer:

= 24.5

Step-by-step explanation:

1 child ticket = 18.50 and they bought 3 so 18.50 x 3 = 55.5

55.5 + 2 adult tickets = 104.50

104.50 - 55.5 = 2 adult tickets

= 49 for 2 adult tickets

49/2 = 1 adult tickets

= 24.5

4 0
2 years ago
What is 22% reduced as a fraction ??
Svet_ta [14]

Answer:

11/50

Step-by-step explanation:

22% is 22/100

So, divide 22/100 by 2 to get 11/50, which cannot be simplified any further.

3 0
3 years ago
What's the x plz help
slavikrds [6]

Answer:

The answer for x is ten

5 0
3 years ago
Factor the polynomial, x2 + 5x + 6
patriot [66]

Answer:

Choice b.

x^{2} + 5\, x + 6 = (x + 3)\, (x + 2).

Step-by-step explanation:

The highest power of the variable x in this polynomial is 2. In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to 0.)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to 0. The discriminant of this polynomial is (5^{2} - 4 \times 1 \times 6) = 1.

\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}.

Similarly:

\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}.

By the Factor Theorem, if x = x_{0} is a root of a polynomial, then (x - x_0) would be a factor of that polynomial. Note the minus sign between x and x_{0}.

  • The root x = -2 corresponds to the factor (x - (-2)), which simplifies to (x + 2).
  • The root x = -3 corresponds to the factor (x - (-3)), which simplifies to (x + 3).

Verify that (x + 2)\, (x + 3) indeed expands to the original polynomial:

\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}.

4 0
3 years ago
Divide <br> (6-q+8q^3-4q^2)/(2q-2)
mestny [16]

Answer:


Step-by-step explanation:

        4q2 + 2q + 3                

 (2q - 2)  l  _  8q3  -  4q2  -  q  +  6                                        

                    8q3  -  8q2                      

                           _  4q2  -  q    

                               4q2 - 4q    

                                     _  3q  +  6  

                                        6q   +  6        

                                       -3q (remainder)  


  4q2 + 2q + 3 -3q / (2q - 2)      


hope this helps

4 0
3 years ago
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