maybe the answer is 4 i don't have an computation but it feels 4
Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
Here
Step-by-step explanation:
We move all terms to the left:
7+9x-(6x-2)=0
We get rid of parentheses
9x-6x+2+7=0
We add all the numbers together, and all the variables
3x+9=0
We move all terms containing x to the left, all other terms to the right
3x=-9
x=-9/3
x=-3
Answer: 6
Step-by-step explanation:
the biggest number that can go into both 24 and 18 evenly is 6. 24/6 is four, and 18/6 is three