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melomori [17]
3 years ago
14

A. B. C. D. Help me please?

Chemistry
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

B: it allow quick conversation to others

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Pleassse help!!!
11111nata11111 [884]

True

Explanation:

Harry Hess in 1961 resurrected Wegener's continental drift hypothesis and also he mantle convection idea of Arthur Holmes by postulating the theory of sea floor spreading.

  • After Wegener's postulation of the continental drift hypothesis, not much was done.
  • It was only around 1931 that Arthur Holmes came up with the idea of a convecting mantle.
  • After the second world war passed, new instruments were used to investigate and map the ocean floor.
  • Through this, Arthur Holmes came up with the idea of a spreading sea floor.
  • This gave a full gleam picture to the idea of a moving earth and the more accepted terminology of "Plate tectonics " came to the fore.

Learn more:

Sea floor spreading brainly.com/question/9912731

Continental drift brainly.com/question/5002949

#learnwithBrainly

8 0
3 years ago
Phosphorous would gain or lose electrons?
devlian [24]

Answer: the valence electron for phosphorus is 5. To achieve an octet electron arrangement, it needs to lose 5 electrons or gain 3 electrons. It is easier to gain 3 electrons than to lose 5 electrons. So phosphorus has to gain 3 electrons.

Explanation:

Hope it helps sorry if it doesn't

4 0
3 years ago
Given the equation: 2H2 + O2 → 2H2O, how many moles of oxygen are needed to react with 13 moles of hydrogen
bulgar [2K]

Explanation:

2H2 + O2 = 2H2O

2mol. 1mol. 2mol

2mol reacts with 1mol

13mol reacts with x

x=<u>13mol</u><u> </u><u>×</u><u> </u><u>1mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>2mol</u>

x= <u>13mol</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2mol

x= 6.5mol of oxygen

6 0
2 years ago
Diamond is forever" is one of the most successful advertising slogans of all time. but is it true? for the reaction shown below,
Zielflug [23.3K]

The given reaction is

C _{(Diamond)}\rightarrow C_{(Graphite)}

An element can exist in 2 or more different forms which have totally different chemical and physical properties. They are known an allotropes.

Diamond and Graphite are allotropic forms of carbon. In the given reaction, diamond is changing to graphite and we have to find out the standard free energy of this reaction. This will help us to find out whether this reaction is spontaneous at 298 K or not.

The following data is needed for calculations which is taken from standard reference table.

H_{f}^{0}(diamond)= 1.895 kJ/mol

H_{f}^{0}(graphite)= 0

S^{0}(diamond)=2.337 J/mol-K

S^{0}(graphite)=5.740 J/mol-K

Step 1: Find ΔH⁰ rxn for the given reaction.

The formula to calculate ΔH⁰ rxn is given below.

\bigtriangleup H^{0}_{rxn}= H_{f}(product)- H_{f}( reactant)

We have graphite on product side and diamond on reactant side.

Therefore, \bigtriangleup H^{0}_{rxn}= H_{f}(graphite)- H_{f}(diamond)

Let us plug in the values given above.

\bigtriangleup H^{0}_{rxn}= 0 - 1.895 kJ/mol

\bigtriangleup H^{0}_{rxn}=  - 1.895 kJ/mol

ΔH⁰ rxn for the given reaction is -1.895 kJ/mol

Step 2 : Find ΔS⁰ rxn for the given reaction.

The formula to calculate ΔS⁰ rxn is

\bigtriangleup S^{0}_{rxn}= S^{0}(product)- S^{0}( reactant)

\bigtriangleup S^{0}_{rxn}= S^{0}(graphite)- S^{0}(diamond)

\bigtriangleup S^{0}_{rxn}= (5.740J/mol.K) - (2.337 J/mol.K)

\bigtriangleup S^{0}_{rxn}= 3.403 J/mol.K

Let us convert this to kJ.

\frac{3.403J}{mol.K}\times \frac{1 kJ}{1000J}= 3.403\times 10^{-3}kJ/mol.K

ΔS⁰ rxn for the given reaction is 3.403 x 10⁻³ kJ/mol.K

Step 3: Find standard free energy ΔG⁰ rxn.

ΔG⁰ rxn for the given reaction is calculated as

\bigtriangleup G^{0}_{rxn}= \bigtriangleup H^{0}_{rxn}- T\times \bigtriangleup S^{0}_{rxn}

We have T = 298 K. Let us plug in the calculated values of ΔH⁰ rxn and ΔS⁰ rxn.

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [(298K)\times 3.403\times 10^{-3}kJ/mol.K]

\bigtriangleup G^{0}_{rxn}= - 1.895 kJ/mol - [1.014 kJ/mol]

\bigtriangleup G^{0}_{rxn}= - 2.909 kJ/mol

The standard free energy change for the given reaction is -2.909 kJ/mol

The negative value of delta G⁰ suggests that the given reaction is spontaneous at room temperature. That means diamond will slowly convert to graphite. The speed of this reaction is extremely slow, but yet the reaction is taking place. So over a period of time diamond will become graphite.

Therefore "Diamond is forever" is not true as it is going to get converted to graphite.

7 0
3 years ago
How many moles of MgCl2 will be produced from 32.0 of Mg(OH)2
vekshin1
1.12 miles of MgCl2 will be produced from the 32.0 of Mg(OH)2
6 0
3 years ago
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