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melomori [17]
3 years ago
14

A. B. C. D. Help me please?

Chemistry
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

B: it allow quick conversation to others

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4 0
3 years ago
quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe
12345 [234]

After 25 days, it remains radon 5.9x10^5 atoms.

Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.

N(Ra) = 5.7×10^7; initial number of radon atoms

t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

n = 25 days / 3.8 days

n = 6.58; number of half-lifes of radon

N1(Ra) = N(Ra) x (1/2)^n

N1(Ra) = 5.7×10^7 x (1/2)^6.58

N1(Ra) = 5.9x10^5; number of radon atoms after 25 days

The half-life is independent of initial concentration (size of the sample).

More about half-life: brainly.com/question/1160651

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6 0
2 years ago
What's the deffinition of igneous rock
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<span>Igneous rocks are those rocks that were formed through cooling and solidifying the molten materials. The best example for igneous rock is solid volcanic java. Lava are liquid that comes from a volcano, but once it is dried and solidify, it becomes a rock and called igneous rock.
Another example is the granite and basalt. And according to research igneous rock comes from the latin word ignis which means fire. Thus this says it all. From a liquid becomes a rock.


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7 0
3 years ago
Read 2 more answers
What is the solubility of MgCO₃ in a solution that contains 0.080 M Mg²⁺ ions? (Ksp of MgCO₃ is 3.5 × 10⁻⁸)
Alchen [17]

Answer: 4.4 x 10^-7

Explanation:

The dissociation equation for this reaction is:

MgCO3 (s) → Mg+2 (aq) + CO3-2 (aq)

\text { So, } k_{s p}=(x+0.08) x (Here 0.08 >>> x )

\begin{aligned}\Rightarrow 3.5 \times 10^{-8} &=0.08 \times x \\\Rightarrow x &=\frac{3.5}{0.08} \times 10^{-8} \\&=4.37 \times 10^{-7} \\\Rightarrow x & \approx 4.4 \times 10^{-7} \mathrm{~M}\end{aligned}

So the solubility MgCO₃ in a solution that containing 0.080 M Mg²⁺ is 4.4 x 10^-7

7 0
2 years ago
The covalent compounds are soluble in:
erik [133]

Answer:

d) Non-polar solvents

8 0
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