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melomori [17]
2 years ago
14

A. B. C. D. Help me please?

Chemistry
1 answer:
Rina8888 [55]2 years ago
6 0

Answer:

B: it allow quick conversation to others

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fredd [130]
So what do you want me to do
Explanation
7 0
2 years ago
This is very urgent please hurry!!?!!??!
yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

a =\frac{F}{m}

A) The box with a mass of 2kg

F = 8 N

a =\frac{8}{2}

a = 4 m/s2

B) The box with the mass of 4kg

a =\frac{8}{4}

a = 2 m/s2

C) The box with a mass of 6kg

a =\frac{8}{6}

a = 1.33 m/s2

D) The box with a mass of 8kg

a =\frac{8}{8}

a = 1 m/s2

3 0
3 years ago
What element forms an ion with an electronic configuration of [Ne] and a –2 charge?
masha68 [24]
Oxygen has 8 electrons it takes 2 electrons to get config of neon and 2 electros mean -2 charge
7 0
3 years ago
5. If a block of wood has a density of 0.6 g/cm3 and a mass of 120 g, what is its volume? (D= M/V)
AlexFokin [52]

Answer:

200 cm^3

Explanation:

V = M/D

V = 120g / (0.6g/cm^3)

V = 200 cm^3

4 0
3 years ago
What mass of silicon dioxide contains 9.72 X10e24 molecules of silicon dioxide?
dangina [55]

Answer:

1033.36g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of SO2 also contains 6.02x10^23 molecules.

1 mole SO2 = 32 + (16x2) = 64g.

Now, If 64g of SO2 contains 6.02x10^23 molecules,

Therefore, Xg of SO2 will contain 9.72x10^24 i.e

Xg of SO2 = (64x9.72x10^24)/6.02x10^23

Xg of SO3 = 1033.36g.

Therefore, 1033.36g of SO2 contains 9.72x10^24 molecules

6 0
3 years ago
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