Answer:
1. y = (-5x/2) + -3
2. y = (3x/2) + 7
Step-by-step explanation:
For both these problems, we simply need to apply point-slope form.
1. The point (0, -3) and the slope that is perpendicular to the line is the reciprocal of the coefficient, slope = -5/2.
From here, we simply apply the formula:
y - y0 = m ( x - x0)
y - -3 = -5/2 ( x - 0 )
y + 3 = -5/2 x
y = (-5x / 2) + -3
2. The point (0, 7) and the slope that is parallel to the line must maintain the same slope. First, we need to rewrite the equation into slope-intercept:
-3x + 2y = 10
2y = 3x + 10
y = 3x/2 + 5
Now we want to apply the point-slope form
y - y0 = m ( x - x0 )
y - 7 = (3/2) (x - 0)
y - 7 = 3x / 2
y = 3x/2 + 7
Cheers.
