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fenix001 [56]
3 years ago
7

When the pH value of a solution is changed from 2

Chemistry
1 answer:
inna [77]3 years ago
6 0

increases my factor of 10

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Given the balanced equation:
Svet_ta [14]
Is there any answer choices before i get started on working out the problem
8 0
3 years ago
ANSWER IN YOUR OWN WORDS!<br> How does the pH of an acid compare with the pH of a neutral solution?
Lady bird [3.3K]

Answer:

A pH of 7 is neutral.A pH of less than 7 is acidic.

Explanation:

5 0
3 years ago
Read 2 more answers
Write a balanced half-reaction describing the reduction of gaseous dioxygen to aqueous oxide anions.
maksim [4K]

<u>Answer:</u> The balanced half reaction is written below.

<u>Explanation:</u>

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

When oxygen gas is reduced to oxide ions, the number of electron transferred are 2

The chemical equation for the reduction of oxygen gas to oxide ions follows:

O_2+2e^-\rightarrow 2O^{2-}

Hence, the balanced half reaction is written above.

8 0
3 years ago
Lana is studying a chemical reaction in which the reactants propane (c3h8) and oxygen gas (o2) react to yield the products carbo
makvit [3.9K]
In such type of problems where reactant and product ratios are calculated one (Launa) should take start from balanced chemical equation. A balanced chemical equations helps in solving such problems. For this purpose chemical equation of this combustion reaction is drawn.

Equation:

                          C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O

Now, According to this balanced equation one molecule of propane reacts with 5 molecules of oxygen to produce 3 molecules of carbon dioxide and 4 molecules of water.

As She is given with 2 molecules of propane and 10 molecules of oxygen, which means that the equation is multiplied by 2. So, the product side must also be multiplied by 2 to balance the equatio (Law of Conservation of Mass).

Result:

                      ( C₃H₁₀ ⁺ 5 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  3 CO₂ ⁺ 4 H₂O ) ₓ 2

                        2 C₃H₁₀ ⁺ 10 O₂  ⁻⁻⁻⁻⁻⁻⁻⁻⁻>  6 CO₂ ⁺ 8 H₂O

So, 6 molecules of carbon dioxide and 8 molecules of water are produced.
8 0
3 years ago
0.7 L of H2 enters a reaction at standard temperature and pressure.
ASHA 777 [7]

Answer:

1.88 × 10²³ particles

Explanation:

Given data:

Volume of H₂ = 0.7 L

Number of particles at STP = ?

Solution:

First of all we will calculate the number of moles of H₂.

PV = nRT

n = PV / RT

n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K

n = 7 atm. L / 22.43 L. atm. mol⁻¹

n = 0.312 mol

it is known that,

2 g H₂ = 1 mol = 6.022 × 10²³ particles

For 0.312 mol

              0.312 × 6.022 × 10²³ particles

                    1.88 × 10²³ particles

6 0
3 years ago
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