Atomic mass Calcium = 40.078 a.m.u
40.078 g ---------------- 6.02x10²³ atoms
165 g -------------------- ??
165 x ( 6.02x10²³) / 40.078 => 2.47x10²⁴ atoms
hope this helps!
Phosphorus - P - Protons = 15, Electrons = 15, Neutrons = 16 - Non-Metal
Lithium - Li - Protons = 3, Electrons = 3, Neutrons = 4 - Metal
Nitrogen - N - Protons = 7, Electrons = 7, Neutrons = 7 - Non-Metal
Copper - Cu - Protons = 29, Electrons = 29, Neutrons = 34 - Metal
Neon - Ne - Protons = 10, Electrons = 10, Neutrons = 10 - Non-Metal
sorry i don’t know about the other questions but i thought i could help with the table!
Additional Info:
number of protons = atomic number
number of electrons = atomic number
number of neutrons = mass number - atomic number
Answer:
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present. Physical properties can be measured without changing a substance's chemical identity
Explanation:
Answer:
It's well Explained below.
Explanation:
First of Excess product of CaCO_3 would be produced due to the fact that there would not be enough CaCl_2 to react with Na_2•CO_3. The main purpose of having stoichiometric quantities is for us to know the correct amount or near the correct amount of each reactant in order to create a product that will be close to the theoretical amount and thus have a higher percent yield.
Answer:
All three are present
Explanation:
Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble:
.
- Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
- Secondly, addition of liquid ammonia would form a precipitate with silver:
; Silver hydroxide at higher temperatures decomposes into black silver oxide:
. - Thirdly, we also know we have
in the mixture, since addition of potassium chromate produces a yellow precipitate:
. The latter precipitate is yellow.