Answer:
<h3>A neutral (no charge) particle found in the nucleus of an atom. ... The atomic number of an atom is equal to the number of protons or neutrons? false. The atomic number is always equal to the atomic mass.</h3>
Answer:
Density of the copper = 8.94g/cm^3
Student A results = 7.3gm/cm^3 ,9.4 gm/cm^3 , 8.3gm/cm^3
Student B results = 8.4 gm/cm^3 , 8.8 gm/cm^3 , 8gm/cm^3
From the observations we conclude that
Student A's result is accurate but not precise as the trials noted are not close to each other.
Student B's result is accurate and precise as the trials noted are close to each other.
Mean density of student A = 7.3 + 9.4 + 8.3 /3 = 8.33gm/cm^3
Mean density of student B = 8.4 + 8.8 + 8 /3 = 8.4 gm/cm^3
both the densities of A and B are 0.5 away from the actual density.
If you could explain what “merkels” are, the question would be more clear.
I think number one is c not sure or not number 2 is C AND NUMBER 3 IS 1 Go with sliding friction number 2 go with rolling friction number 3 is static friction and 4 is force
<h3>
Answer:</h3>
6.68 g MgSO₄
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Aqueous Solutions</u>
- Molarity = moles of solute / liters of solution
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.965 L
0.0575 M
<u>Step 2: Identify Conversions</u>
Molar Mass of Mg - 24.31 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol
<u>Step 3: Find MgSO₄</u>
- Substitute [M]: 0.0575 M = x / 0.965 L
- Isolate <em>x</em>: 0.055488 mol MgSO₄ = x
- Rewrite: x = 0.055488 mol MgSO₄
<u>Step 4: Convert</u>
<u />
= 6.67959 g MgSO₄
<u>Step 5: Check</u>
<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>
6.67959 g MgSO₄ ≈ 6.68 g MgSO₄