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mojhsa [17]
3 years ago
9

Which process takes place when large rocks crumble due to oxidation?

Chemistry
2 answers:
jok3333 [9.3K]3 years ago
4 0
Abrasion is the answer
VashaNatasha [74]3 years ago
3 0

Answer:

This question is incomplete but the completed question is below

Which process takes place when large rocks crumble due to oxidation?

A) Erosion

B) Deposition

C) physical weathering

D) chemical weathering​

The correct option is D

Explanation:

Weathering can simply be defined as the breakdown of the top surface of rocks. <u>From this definition, it can be deduced that the question describes a type of weathering</u>. Weathering can be of two types; Physical weathering and chemical weathering.

Physical weathering is caused by physical components of the environment such as temperature, water and some activities of living organisms. Physical weathering does not alter the chemical composition of the rock. A <u>chemical weathering</u> is caused by a reaction between the components of the rock and another substance. This type of weathering <u>involves a chemical reaction (for example oxidation)</u> which leads to the breakdown of the rock.

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The atomic number is always equal to the atomic mass true false
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Answer:

<h3>A neutral (no charge) particle found in the nucleus of an atom. ... The atomic number of an atom is equal to the number of protons or neutrons? false. The atomic number is always equal to the atomic mass.</h3>
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3 years ago
The density of copper is listed as 8.94g/cm​ 3​ . Two students each make three density determinations of samples of the substanc
amm1812

Answer:

Density of the copper = 8.94g/cm^3

Student A results = 7.3gm/cm^3 ,9.4 gm/cm^3 , 8.3gm/cm^3

Student B results = 8.4 gm/cm^3 , 8.8 gm/cm^3 , 8gm/cm^3

From the observations we conclude that

Student A's result is accurate but not  precise as the trials noted are not close to each other.

Student B's result is accurate and precise as the trials noted are close to each other.

Mean density of student A = 7.3 + 9.4 + 8.3 /3 = 8.33gm/cm^3

Mean density of student B = 8.4 + 8.8 + 8 /3 = 8.4 gm/cm^3

both the densities of A and B are 0.5 away from the actual density.

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3 years ago
What is “ location of the merkels cells “
frez [133]
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4 years ago
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8 0
3 years ago
How many grams of magnesium<br> sulfate (MgSO4) are dissolved in<br> 0.965 L of a 0.0575 M solution?
JulsSmile [24]
<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.965 L

0.0575 M

<u>Step 2: Identify Conversions</u>

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

<u>Step 3: Find MgSO₄</u>

  1. Substitute [M]:                     0.0575 M = x / 0.965 L
  2. Isolate <em>x</em>:                              0.055488 mol MgSO₄ = x
  3. Rewrite:                               x = 0.055488 mol MgSO₄

<u>Step 4: Convert</u>

<u />\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} ) = 6.67959 g MgSO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0
3 years ago
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