Answer:
ac = 204 [m/s²]
Explanation:
To solve this problem we must use the following equation that relates the tangential velocity to the radius of rotation.
ac = v²/r
where:
v = tangential velocity = 15 [m/s]
r = radius = 1.1 [m]
Now replacing we have:
ac = (15)²/1.1
ac = 204 [m/s²]
I think the answer is true
Answer:
acceleration
acceleration is the rate at which velocity change
i think
An atom or ion which does not have the same electronic configuration as the species [kr] is K+
The complete question is given below:
An atom or ion has the abbreviated electron configuration (Kr). Select the species that it could not A. Br" B. K+ C. Sr24 D. Rbt E. Se-
<h3>What is an atom?</h3>
An atom can be defined as the smallest particle of an element which can take part in a chemical reaction.
Some elements are
- Monoatomic; eg: C
- Diatomic; eg: O2
- Triatomic and others
- Polyatomic
So therefore, an atom or ion which does not have the same electronic configuration as the species [kr] is K+
Learn more about atoms or ions of elements:
brainly.com/question/6258301
Answer:
or 0.32 μm.
Explanation:
Given:
The radiations are UV radiation.
The frequency of the radiations absorbed (f) = 
The wavelength of the radiations absorbed (λ) = ?
We know that, the speed of ultraviolet radiations is same as speed of light.
So, speed of UV radiation (v) = 
Now, we also know that, the speed of the electromagnetic radiation is related to its frequency and wavelength and is given as:
Now, expressing the above equation in terms of wavelength 'λ', we have:
Now, plug in the given values and solve for 'λ'. This gives,
![\lambda=\frac{3\times 10^8\ m/s}{9.38\times 10^{14}\ Hz}\\\\\lambda=3.2\times 10^{-7}\ m\\\\\lambda=3.2\times 10^{-7}\times 10^{6}\ \mu m\ [1\ m=10^6\ \mu m]\\\\\lambda=3.2\times 10^{-1}=0.32\ \mu m](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B3%5Ctimes%2010%5E8%5C%20m%2Fs%7D%7B9.38%5Ctimes%2010%5E%7B14%7D%5C%20Hz%7D%5C%5C%5C%5C%5Clambda%3D3.2%5Ctimes%2010%5E%7B-7%7D%5C%20m%5C%5C%5C%5C%5Clambda%3D3.2%5Ctimes%2010%5E%7B-7%7D%5Ctimes%2010%5E%7B6%7D%5C%20%5Cmu%20m%5C%20%5B1%5C%20m%3D10%5E6%5C%20%5Cmu%20m%5D%5C%5C%5C%5C%5Clambda%3D3.2%5Ctimes%2010%5E%7B-1%7D%3D0.32%5C%20%5Cmu%20m)
Therefore, the wavelength of the radiations absorbed by the ozone is nearly or 0.32 μm.
