If you toss a pair of dice
1,000 times, how many times would you expect to get a sum of 12 as the result. When
you toss a die there is 1/6 probility that you will get 6 so if you toss
another die the probability is the same. The get a sum of 12 the probability is
1/36.
So if you toss 1000 times,
<span>You will get about 1000
(1/36) = 27 times</span>
The generic equation is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
m = (0-1) / (4-3)
m = (- 1) / (1)
m = -1
The ordered pair is:
(xo, yo) = (4, 0)
Substituting values:
y-0 = -1 * (x-4)
y = -x + 4
Answer:
y = -x + 4
option 1
On your X-axis, go to -5 and identify which Y-coordinate it is. For this problem, it would be -2.
Answer:
Step-by-step explanation:
Time for first clock is 8:34
Time for second clock is 11:48
subtract them: 11 hrs. 48 min.
- 8 hrs. 34 min.
_____________
3 hrs. 14 min.
