I would have to say That i see 8
Step-by-step explanation:
x=y+9
substitute
3(y+9)+8y=-6
3y+27+8y= -6
13y = -6 -27
13y= -33
y = -33/13
x = -33/13 + 9
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
8963.46
Step-by-step explanation:
84*66 for the rectangle and since there is two semi circles you could just calculate it as one so it would be 84*66+33*33*3.14 because formula for area of circle is A= pi*raduis with exponant of 2
A)Add 3 and the continue to add 2 more to three each time to get the next number
B)add 1 and add one to the number one each time to get the the next number