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Elza [17]
3 years ago
5

Jim went for a 3.75 hour run. How many minutes did he run?

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0
An hour is 60 minutes. So you multiple the hot by 60. You get 180 minutes plus the 75 remaining minutes. The answer is 255
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What is the number of electrons will chlorine most likely gain/lose
LuckyWell [14K]

Gain 1.

This is because of Chlorine's placement on the periodic table. Chlorine is a Halogen, thus being located in group 17 or 7A. This means it is one of the closest elements to being a Noble Gas or group 18/8A.

Chlorine has 7 valence electrons, and in order for it to become a Noble Gas, it needs 8. Cl- is typically the symbol used to represent this as Chlorine needs to gain an electrons instead of lose; once Chlorine gains the electron, it will be stable.

This also means that Chlorine has a high ionization energy or, in simpler terms, it would be difficult to remove an electron from Chlorine.

Hope this helps!

8 0
3 years ago
Which compound could serve as a reactant in a neutralization reaction ?
Veseljchak [2.6K]
 The   compound that  could serve  as  a reactant   in the neutralization reaction is    H2SO4
     
  Explanation
   Neutralization reaction occur  between an acids  and a base. H2SO4             (  sulfuric acid)  is  a strong  acid.  It can be neutralized by  strong base such as NaOH ( sodium  hydroxide)

  Example of neutralization reaction is

2NaOH + H2SO4 → Na2SO4  + 2H2O
7 0
2 years ago
Noclouttrio -inta ………………….!.!.!!..!
Ronch [10]

Answer:

3 more brlst

Explanation:

4 0
2 years ago
Many of the motions of tje solar system are regular and predictable, meaning they happen over and over in a pattern . Identify o
son4ous [18]
The orbits of the plants are fixed around the sun by the suns gravitational pull
6 0
3 years ago
Calculate the silver ion concentration in a saturated
Stolb23 [73]

Answer:

0.015 M

Explanation:

Let's consider the solution of silver (I) sulfate.

Ag₂SO₄(s) ⇄ 2 Ag⁺(aq) + SO₄²⁻(aq)

In order to find the solubility (S) of silver (I) sulfate, we will use an ICE chart.

    Ag₂SO₄(s) ⇄ 2 Ag⁺(aq) + SO₄²⁻(aq)

I                               0               0

C                            +2S           +S

E                               2S            S

The solubility product (Ksp) is:

Ksp = 1.4 × 10⁻⁵ = [Ag⁺]².[SO₄²⁻] = (2S)².S = 4S³

S = 0.015 M

4 0
3 years ago
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