Answer:
Option (B) is correct
Explanation:
Oxidation: 
Reduction: 
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Overall: 
Nernst equation for this cell reaction at 
:
![E_{cell}=(E_{Sn^{2+}\mid Sn}^{0}-E_{Zn^{2+}\mid Zn}^{0})-\frac{0.059}{n}log\frac{[Zn^{2+}]}{[Sn^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D%28E_%7BSn%5E%7B2%2B%7D%5Cmid%20Sn%7D%5E%7B0%7D-E_%7BZn%5E%7B2%2B%7D%5Cmid%20Zn%7D%5E%7B0%7D%29-%5Cfrac%7B0.059%7D%7Bn%7Dlog%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BSn%5E%7B2%2B%7D%5D%7D)
Where, n is number of electron exchanged and species inside third bracket represents concentrations in molarity.
Here, n = 2, 
and ![[Zn^{2+}]=2.5\times 10^{-3}M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%3D2.5%5Ctimes%2010%5E%7B-3%7DM)
So, plug in all the given values into above equation:
![0.660V=(-0.136V+0.76V)-\frac{0.059}{2}log\frac{2.5\times 10^{-3}M}{[Sn^{2+}]}](https://tex.z-dn.net/?f=0.660V%3D%28-0.136V%2B0.76V%29-%5Cfrac%7B0.059%7D%7B2%7Dlog%5Cfrac%7B2.5%5Ctimes%2010%5E%7B-3%7DM%7D%7B%5BSn%5E%7B2%2B%7D%5D%7D)
So, ![[Sn^{2+}]=4.2\times 10^{-2}M](https://tex.z-dn.net/?f=%5BSn%5E%7B2%2B%7D%5D%3D4.2%5Ctimes%2010%5E%7B-2%7DM)
As the value "0.059" varies from literature to literature and 
is most closest to 
therefore option (B) is correct.
Answer:
How do you find pressure given moles volume and temperature?
Therefore, to convert the moles of gas to pressure, the scientist must know the volume and temperature of the gas, in addition to the number of moles of gas. The pressure is then given by P = nRT / V.
The statement that best describes the effect of low ionization energies and low electronegativities on metallic bonding is the first one - the valence electrons are easily delocalized.
Due to these low energies and negativities, valence electrons can be moved around quite easily and their positions may be altered quite drastically.
Answer:
C is the only reasonable answer.. but this is 6th grade science and I'm in 7th, so I'm pretty sure I'm right
