The correct answer to the question that is being presented above would be letter c. change in particle size. Changes in pressure, temperature, and concentration are stressors that cause change in chemical equilibrium.
190 g of water
60 g of KI
Explanation:
For concentration expressed in mass percentage of the solution we have the following formula:
concentration / 100 = mass of the dissolved / mass of the solution
mass of the dissolved KI = (concentration × mass of the solution) / 100
mass of the dissolved KI = (24 × 250) / 100 = 60 g
mass of the solution = mass of the water + mass of the dissolved KI
mass of the water = mass of the solution - mass of the dissolved KI
mass of the water = 250 - 60 = 190 g
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mass percent concentration
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Answer: 367 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number
of particles.
Enthalpy of vaporization is the amount of heat released when 1 mole of substance is converted from liquid to gaseous state.
Given : Enthalpy of vapourization of
= 17.4 kJ/mol
To calculate the number of moles, we use the equation:


1 mole of
produces heat = 17.4 kJ
8.3 moles of
produces heat = 
Given : Enthalpy of vapourization of
= 6.0 kcal/mol =
(1kcal=4.184kJ)
25.104 kJ heat is produced by = 1 mole of
144 kJ heat is produced by =
of
Mass of 
Thus 367 grams of
must be evoparated o remove as much heat as evaporation of 1.00 kg of 
<u>Answer:</u> The volume of hydrogen gas required for the given amount of ethylene gas is 113 L
<u>Explanation:</u>
At STP:
1 mole of a gas occupies 22.4 L of volume
We are given:
Volume of ethylene = 113 L
For the given chemical equation:

By Stoichiometry of the reaction:
of ethylene reacts with
of hydrogen gas
So, 113 L of ethylene gas will react with =
of hydrogen gas
Hence, the volume of hydrogen gas required for the given amount of ethylene gas is 113 L