"a quantity representing the amount of water vapor in the atmosphere or a gas."
Answer:
The percent by mass of copper in the mixture was 32%
Explanation:
The ammount of HNO₃ used is:
mol HNO₃ = volume * concentration
mol HNO₃ = 0.015 l * 15.8 mol/l
mol HNO₃ = 0.237 mol
According to the reaction, 4 mol HNO₃ will react with 1 mol Cu and produce 1 mol Cu²⁺. Since we have 0.237 mol HNO₃, the amount of Cu that could react would be (0.237 mol HNO₃ * 1 mol Cu / 4 mol HNO₃) 0.06 mol. This reaction would produce 0.060 mol Cu²⁺, however, only 0.010 mol Cu²⁺ were obtained, indicating that only 0.010 mol Cu were present in the mixture. This means that the acid was in excess, so we can assume that all copper present in the mixture has reacted.
Since 0.010 mol of Cu²⁺ were produced, the amount of Cu was 0.01 mol.
1 mol of Cu has a mass of 63.5 g, then 0.01 mol has a mass of:
0.01 mol Cu * 63.5 g / 1 mol = 0.635 g.
Since this amount was present in 2.00 g mixture, the amount of copper in 100 g of the mixture will be:
100 g(mixture) * 0.635 g Cu / 2 g(mixture) = 32 g
Then, the percent by mass of Cu (which is the mass of Cu in 100 g mixture) is 32%
I think it is with screens l, chemicals, and filters
I hope this helped
Answer:
The rate determining step depends on the
Explanation:
The rate determining step depends on the mechanism of the reaction. If it proceeds by E1 reaction mechanism, it produces 1-methylcyclohexene while the E3 reaction mechanism gives 3-methylcyclohexene. The rate determining step for E1 is an intermediate that is formed when protonation of the hydroxyl group occurs to form H3O+ followed by electrophilic attack on the carbocation formed to absorb the hydrogen making the carbon atom -CH2 and forming a double bond between.
The E3 mechanism is similar only that the attack on the carbon atom is done at the -C3 instead of -C1.
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