A sample liquid is heated in a closed container until it changes to gas.what happens to the size of the particles in the sample

2 answers:

8 0

Nothing happens to these particles when it comes to size however if it were to be speed, the sample would increase.
Fact: The size of a particle will never change!

elena-14-01-66 [18.8K]3 years ago

4 0

Answer: Size of the particles will never change

Explanation: When a sample liquid is heated in a closed container, the temperature increases and thereby increasing the speed of the particles which would try to escape the surface of water into the free space above the liquid. This process is known as Vaporization and since its a closed container, it will take the form of the condensed vapors on the surface lid of the container.

Thus in no process would the size of the particle change as temperature affects only the speed of the container, not the size of the particles.

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<h2>Answer:</h2>

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<h2>General Formulas and Concepts:</h2><h3><u>Chemistry</u></h3>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<h2>Explanation:</h2>

<u>Step 1: Define</u>

2.3 × 10²⁴ formula units KNO₃

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

<u>Step 3: Convert</u>

<u /> $2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )$ = 386.172 g KNO₃