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galina1969 [7]
3 years ago
6

9. What type of bonds hold polyatomic ions together?

Chemistry
2 answers:
Mrac [35]3 years ago
8 0
B. Is the answer I'm pretty sure
ella [17]3 years ago
5 0
The answer is B Covalent bonds
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Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the
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3 years ago
What is the nuclear binding energy of an atom that has a mass defect of 5.0446
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Answer:

<em>Option C: 4.54 x </em>10^{11}<em> KJ/mol of nuclei</em>

<em>Note: </em>Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}.

Explanation:

If mass defect is known, then nuclear binding energy can easily be calculated, here's how:

First step is to convert that mass defect into kg.

Mass defect = 5.0446 amu

Mass defect = 5.0466 x 1.6606 x 10^{-27}

Because 1 amu = 1.6606 x 10^{-27} Kg.

<em>Mass defect = 8.383 x </em>10^{-27}<em> kg.</em>

Now, we need to find out it's energy equivalent by using following equation:

Using the equation E = mc²:

where c= 3.00 x 10^{8} m/s²

E = (8.383 x 10^{-27}) x (3.00 x 10^{8})²

E = 7.54 x 10^{-10} J  this energy is in Joules but nuclear binding energy is usually expressed in KJ/mol of nuclei. Let's convert it:

(7.54 x 10^{-10} Joule/nucleus)x(1 kJ/1000 Joule)x(6.022 x 10^{23} nuclei/mol) =  

<em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em>

E = <em>4.54 x </em>10^{11}<em> kJ/mol of nuclei .</em> So, this is the nuclear binding energy of that atom, which is option  C.

<em>Note:</em> Here in this question option C is not correctly put. It is 4.54 x10^{11} rather than 4.54 x 10^{-123}

4 0
4 years ago
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Answer:

Lithium selenide Lithium selenide (Li2Se) 12136-60-6 Dilithium selenide lithium selenidolithium

Molecular Weight 92.9 g/mol

Dates Modify 2020-11-15 Create 2005-08-08

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If m&lt; CAB = 80 degrees, then find m&lt; BAD
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30

Explanation:

Just trust me

7 0
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A chemist determined by measurements that 0.050 moles of tin participated in a chemical reaction. Calculate the mass of tin that
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Answer:

Explanation:

MM of I2 = 2 (127 g) = 254 g/mol

0.065 mol I2 x 254g I₂/ 1 mol I₂  = 16.5 g I2

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