Answer: NO2
Explanation:
N O
Divide each by its 25.93 74.07
mass number 14 16
2 4
Divide both by the 2 2
smaller (i.e. 2) 1 2
Therefore, the empirical formula = NO2
Answer:
b) [Kr] 5s² 4d¹⁰ 5p⁵
Explanation:
Properties of iodine:
Iodine is present in group seventeen.
It is halogen element.
Its atomic mass is 127 amu.
Its atomic number is 53.
It is present in solid form.
It is crystalline in nature.
It is very corrosive and has pungent odor.
It can not react with oxygen and nitrogen.
Electronic configuration:
I₅₅ = 1s² 2s² 2p⁶ 3s³ 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration:
I₅₅ = [Kr] 5s² 4d¹⁰ 5p⁵
Abbreviated electronic configuration is shortest electronic configuration by using the noble gases.
Answer:
14.945798 in us fluid ounce
Explanation:
Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.
Explanation:
The reaction equation is as follows.
Initial : 0.3 0.4 0
Change: -x -x x
Equilbm: (0.3 - x) (0.4 - x) x
We know that, relation between standard free energy and equilibrium constant is as follows.
Putting the given values into the above formula as follows.
x = 0.1417
Hence, at equilibrium
= 0.1583 M
= 0.2583 M
Answer: It would be Sp2, because H3O+ has planar structure.