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sineoko [7]
4 years ago
9

La precipitación ácida es un agente de?

Chemistry
1 answer:
serg [7]4 years ago
4 0

Answer:

acid precipitation is an agent of

Explanation:

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What’s the answer I don’t know how to do it
Inessa05 [86]

Answer:

3.63m/s²

Explanation:

Given parameters:

Mass of box  = 8kg

Net force  = 29N

Unknown:

Acceleration of the box = ?

Solution:

To solve this problem, we use Newton's second law of motion which is stated as;

       Force  = mass x acceleration

 Acceleration  = \frac{Force }{mass}   = \frac{29}{8}  

Acceleration  = 3.63m/s²

5 0
3 years ago
Phosphorus-32 has a half-life of 14.0 days. Starting with 6.00 g of 32P, how many grams will remain after 42.0 days ?
aleksandrvk [35]
6g...........3g..........1,5g........0,75g
0d..........14d.........28d.........42d

After 42 days 0,75g of Phoshorus-32 will remain.
4 0
3 years ago
Read 2 more answers
A photon with 2.3 eV of energy can eject an electron from potassium. What is the corresponding wavelength of this type of light?
Ira Lisetskai [31]

Answer:

\lambda=540.16\ nm

Explanation:

Given that:

The energy of the photon = 2.3 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.60 × 10⁻¹⁹ J

So, Energy = 2.3\times 1.60\times 10^{-19}\ J=3.68\times 10^{-19}\ J

Considering

Energy=\frac {h\times c}{\lambda}

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Thus,  

3.68\times 10^{-19}=\frac {6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\frac{3.68}{10^{19}}=\frac{19.878}{10^{26}\lambda}

3.68\times \:10^{26}\lambda=1.9878\times 10^{20}

\lambda=5.40163\times 10^{-7}\ m=540.16\times 10^{-9}\ m

Also,  

1 m = 10⁻⁹ nm

So,  

\lambda=540.16\ nm

3 0
4 years ago
What is chemical symbol for potassium
Vinvika [58]

Answer:

K is the symbol for potassium

4 0
3 years ago
Read 2 more answers
100 cm3 of the copper sulfate solution contains 1.8 g of copper sulfate.
elixir [45]

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution  = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m  = 25×0.018 g = 0.45 g

∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g

8 0
3 years ago
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