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drek231 [11]
3 years ago
9

A 0.75mol calcium carbonate (CaCO3) pellet has what mass?

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
4 0

Answer:

75 g  

Step-by-step explanation:

<em>Step 1. </em>Calculate the molar mass of CaCO₃

Ca                    =   40.08

  C                    =   12.01

3O = 3 × 16.00 = <u>  48.00 </u>

               Total = 100.09 g/mol

<em>Step 2</em>. Calculate the mass of the pellet

Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)

Mass of CaCO₃ = 75 g

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Answer:

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3 years ago
Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve
pochemuha

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.

The balanced neutralization equation is:

NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)

  • Step 1: Calculate the reacting moles of KHP.

0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.

0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol

  • Step 2: Determine the reacting moles of NaOH.

The molar ratio of NaOH to KHP is 1:1.

1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH

  • Step 3: Calculate the molarity of NaOH.

1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.

[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Learn more about titration here: brainly.com/question/4225093

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3 years ago
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i would say B? Im sorry if im wrong

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