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3 years ago

A 0.75mol calcium carbonate (CaCO3) pellet has what mass?

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

4 0

Answer:

75 g

Step-by-step explanation:

Step 1. Calculate the molar mass of CaCO₃

Ca = 40.08

C = 12.01

3O = 3 × 16.00 = 48.00

Total = 100.09 g/mol

Step 2. Calculate the mass of the pellet

Mass of CaCO₃ = 0.75 mol × (100.09 g/1 mol)

Mass of CaCO₃ = 75 g

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Chose the two factors that work together to create the global wind patterns that operate in the atmosphere.

grin007 [14]

Global wind patterns are mainly determined by unequal heating of the earth's surface, changes in air pressure, and earth's rotation. Change in air pressure: Air mainly circulates due to change in air pressure. It moves from a region of high air pressure to the region of lower air pressure.

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3 years ago

Se ha añadido un evaporador para una alimentación de 11500 kg/dia de zumo de pomelo de forma que evapore 3000 kg/dia de agua por

mamaluj [8]

Answer:

37 %.

Explanation:

¡Hola!

En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:

$F_{sol}=11500kg/dia-3000kg/dia=8500 kg/dia$

Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:

$x_z^{entra}*11500kg/dia=x_z^{sale}*8500kg/dia$

Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:

$x_z^{entra}=\frac{x_z^{sale}*8500kg/dia}{11500kg/dia} =\frac{0.50*8500kg/dia}{11500 kg/dia}\\ \\x_z^{entra}=0.37$

Que es igual al 37%.

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6 0

3 years ago

For the following reaction, 4.31 grams of iron are mixed with excess oxygen gas . The reaction yields 5.17 grams of iron(II) oxi

natka813 [3]

Answer: The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Iron:

Given mass of iron = 4.31 g

Molar mass of iron = 53.85 g/mol

Putting values in above equation, we get:

$\text{Moles of iron}=\frac{4.31g}{53.85g/mol}=0.0771mol$

For the given chemical reaction:

$2Fe(s)+O_2(g)\rightarrow 2FeO(s)$

By Stoichiometry of the reaction:

2 moles of iron produces 2 moles of iron (ii) oxide.

So, 0.0771 moles of iron will produce = $\frac{2}{2}\times 0.0771=0.0771mol$ of iron (ii) oxide

Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:

Moles of of iron (II) oxide = 0.0771 moles

Molar mass of iron (II) oxide = 71.844 g/mol

Putting values in equation 1, we get:

$0.0771mol=\frac{\text{Theoretical yield of iron(ii) oxide}}{71.844g/mol}=5.53g$

To calculate the percentage yield of iron (ii) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of iron (ii) oxide = 5.17 g

Theoretical yield of iron (ii) oxide = 5.53 g

Putting values in above equation, we get:

$\%\text{ yield of iron (ii) oxide}=\frac{5.17g}{5.53g}\times 100\\\\\% \text{yield of iron (ii) oxide}=93.49\%$

Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %

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Answer:

pineal body is a vastigious structure which signifies same origin of chimpanzee and modern man

Explanation:

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3 years ago

Earth's atmosphere, which traps heat and radiation from the sun, helps to keep our temperature somewhat stable, even when we are

Elis [28]

Answer:

It is true

Explanation:

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3 years ago

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