In determining the boiling point
of solutions, always take note of the number of ions that will dissociate in
the solution. It does not depend on the nature of the substance. The greater
the number of ions dissociated, the greater is the boiling point of the solution.
Answer:
CuSO4(aq)
Explanation:
The aqueous for of CuSO₄ is an electrolyte and it will conduct electricity.
CuSO₄ is an ionic substance and in solid state, it will not have the ability to conduct electricity.
- In aqueous form, it will contain free mobile ions which serves as carriers of electric current.
- In the solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
- The remaining given compounds will not conduct electricity as they are non-polar and do not have free mobile electrons.
Answer:
150 g/mol
Explanation:
Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.
H₂X + 2 NaOH → Na₂X + 2 H₂O
40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:
0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol
The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.
4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:
0.600 g/4.00 × 10⁻³ mol = 150 g/mol
0.555 = 1.90/V
⇒ V = 1.90/0.555
⇒ V = 3.423 liter
