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2 years ago

As more resistors are added in parallel across a constant voltage source, the power supplied by the source

1 answer:

6 0

As more resistors are added in parallel across a constant voltage source, there are more paths for current to take. So more current dribbles out of the source, and the total current supplied by the source increases.

The power supplied by the battery is (voltage) x (current). So if the voltage is constant and the current increases, the power being supplied must also increase.

choice-c

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____ is a pesticide that influenced society by increasing crop yield, but it also caused human and animal sickness.

Ilya [14]

I think your answer would be DDT, but don't hold me to it

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3 years ago

Strontium−90 is one of the products of the fission of uranium−235. This strontium isotope is radioactive, with a half-life of 28

Ludmilka [50]

Answer : The time passed in years is 20.7 years.

Explanation :

Half-life = 28.1 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{28.1\text{ years}}$

$k=2.47\times 10^{-2}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $2.47\times 10^{-2}\text{ years}^{-1}$

t = time passed by the sample = ?

a = initial amount of the reactant = 1.00 g

a - x = amount left after decay process = 0.600 g

Now put all the given values in above equation, we get

$t=\frac{2.303}{2.47\times 10^{-2}}\log\frac{1.00}{0.600}$

$t=20.7\text{ years}$

Therefore, the time passed in years is 20.7 years.

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3 years ago

What day of the year is solar time the same as sidereal time?

Illusion [34]

Answer:

I think the answers March 21

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2 years ago

Read 2 more answers

Min is asked to balance the equation below.

Minchanka [31]

It is incorrect, because the identity of the original product has changed. Ca3(OH)2 does not exist! It is no longer calcium hydroxide. To balance an equation, you must manipulate the coefficients, a.k.a. the big numbers that go before reactants or products. Subscripts, the little numbers inside the reactants or products, cannot be changed without completely changing the substance.

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3 years ago

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a liquid with a specific heat of 1900J/Kg° C has 4750 joules of heat energy is added to it. if the temperature increases from 20

GREYUIT [131]

E=mcθ
where E is the energy added,m is the mass,c is the specfic heat capacity and θ is the change in temprature.
making m subject u get E/cθ=m
θ=(30-20)=10
plugging the values we get :
 $\frac{4750}{1900*10}$

solving it we get the answer that is 0.25kg or 250 grams

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2 years ago