Answer:
The density of the lead, ρ = 11.35 g /cm³
Explanation:
Given,
The mass of the lead, m = 567.5 g
The volume of the lead, v = 50 cm
The density is given by the relation
ρ = m / v
Substituting the given values in the above equation,
ρ = 567.5 g / 50 cm
= 11.35 g /cm³
Hence, the density of the lead, ρ = 11.35 g /cm³
option A is the correct answer, if the gravitational acceleration is taken 10m/s²(rounding of 9.8/ms²).
hope this helps you.
Presión
765
=
ATMÓSFERA
1,00658
