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V125BC [204]
3 years ago
10

What is the potential difference across a 15Ω resistor that has a current of 3.0 A?

Physics
2 answers:
ololo11 [35]3 years ago
7 0

Answer:

45 V

Explanation:

sesenic [268]3 years ago
6 0

V = I • R

V = (15 ohms) x (3 A)

V = 45 volts

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How can global climate change be studied
Marina CMI [18]
Not sure... need help with it 


4 0
3 years ago
Assessing and monitoring your fluid levels will help you optimize your car's _______.
juin [17]

Answer:

A. fuel mileage and longevity          

Explanation:

           For a person purchasing a car, car longevity is one of the main concern. They are also interested in many things such as maximum mileage and service life.

           By properly monitoring and assessing few measures one can maintain the efficiency and longevity of the car. One such thing is by monitoring the liquid levels of the car. Certain liquids like the coolant or radiator water level should be well maintain in proper level in order to run the car economically.

Thus by doing this, one can optimize the car's longevity and the fuel mileage.

Hence the correct option is (A).

3 0
3 years ago
Two astronauts, each having a mass of 74.3 kg are connected by a 13.1 m rope of negligible mass. They are isolated in space, orb
murzikaleks [220]

Answer:

  L = 5076.5 kg m² / s

Explanation:

The angular momentum of a particle is given by

         L = r xp

         L = r m v sin θ

the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1

as we have two bodies

       L = 2 r m v

let's find the distance from the center of mass, let's place a reference frame on one of the masses

        x_{cm} = \frac{1}{M} \sum  x_{i} m_{i}i

        x_{cm} = \frac{1}{m+m} ( 0 + l m)

        x_{cm} = \frac{1}{2m}  lm

        x_{cm} = \frac{1}{2}

        x_{cm} = 13.1 / 2 = 6.05 m

let's calculate

          L = 2  6.05  74.3  5.65

          L = 5076.5 kg m² / s

4 0
3 years ago
Read 2 more answers
You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sin
faust18 [17]

Answer:

Frequency required will be 2421.127 kHz

Explanation:

We have given inductance L=0.450H=0.45\times 10^{-3}H

Current in the inductor i=1.90mA=1.90\times 10^{-3}A

Voltage v = 13 volt

Inductive reactance of the circuit X_l=\frac{v}{i}

X_l=\frac{13}{1.9\times 10^{-3}}=6842.10ohm

We know that

X_l=\omega L=2\pi fL

2\times 3.14\times  f\times 0.45\times 10^{-3}=6842.10

f = 2421.127 kHz

6 0
3 years ago
Long periods of unusually low precipitation are called?
DiKsa [7]
I think it is called a drought but i would look it up
6 0
3 years ago
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