Question

A rock hits the ground with a speed of 13 m s−1

Answer 1

Answer:

3.55kg

Explanation:

K. E = ½mv²

Where m = mass,  v = velocity

K. E = 300J

v = 13m/s

Therefore,

K. E = ½mv²

300 = ½ × m × 13²

Multiply both sides by 2

600 = m × 169

Divide both sides by 169

m = 600 ÷ 169

mass = 3.55kg

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