A rock hits the ground with a speed of 13 m s−1

Physics

1 answer:

polet [3.4K]3 years ago

4 0

Answer:

3.55kg

Explanation:

K. E = ½mv²

Where m = mass, v = velocity

K. E = 300J

v = 13m/s

Therefore,

K. E = ½mv²

300 = ½ × m × 13²

Multiply both sides by 2

600 = m × 169

Divide both sides by 169

m = 600 ÷ 169

mass = 3.55kg

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What is the volume of a rock with a density of 3.00 g/cm3 and a mass of 600g?

Mademuasel [1]

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now we divide D on both sides giving us
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viktelen [127]

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