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sergejj [24]
3 years ago
6

A student prepares an iron standard solution in a 50.00 mL volumetric flask. The iron stock concentration is 0.0001974 M. A stud

ent dispenses 29.80 mL of stock iron solution into the volumetric flask, adds the reagents, and dilutes to volume with H2O. The concentration of the iron standard is:
Chemistry
1 answer:
Serhud [2]3 years ago
4 0

Answer:

0.00011765 M

Explanation:

When a solution is prepared by dilution, the volumes and concentrations are related by:

C1*V1 = C2*V2

Where C1 is the concentration of the solution 1, V1 is the volume of the solution 1, C2 is the concentration of solution 2, and V2 is the volume of solution 2.

The stock solution is the solution 1, and the standard solution, the solution 2, so:

0.0001974*29.80 = C2*50.00

C2 = 0.00011765 M

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The correct answer for primary component of phosphate buffer at pH = 7.4 is H₂PO₄⁻ and HPO₄²⁻ .

<u>Buffer solution :</u>

It is a solution of mixture of weak acid and its conjugate base OR weak base and its conjugate acid . It resist any change in solution when small amount of strong acid or base is added .

<u>Capacity of a good buffer : </u>

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<u>Phosphate Buffer : </u>

Phosphate may have three types of acid-base pairs at different pka ( shown in image ).

Since the question is asking the pH = 7.4

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If image is checked the acid - base pair  " H₂PO₄⁻ and HPO₄²⁻  has pka 7.2 which is near to pH = 7.4 .

Hence we can say  , the primary chemical component of phosphate buffer at pH = 7.4  is H₂PO₄⁻ and HPO₄²⁻  .


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