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cupoosta [38]
2 years ago
13

Given the following equation: 2NaClO3 --> 2NaCl + 3O2

Chemistry
1 answer:
Dimas [21]2 years ago
8 0
I’m not an expert and I haven’t taken chemistry in like a year but i believe you use stoichiometry to do this equation. It should look something like this.

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PLEASE help i will give brainly if someone answers A pleeease help it will help me answer my other questions
Sedaia [141]

Answer:

a.Archaeopteryx

b.Archaeopteryx had more in common with other small Mesozoic dinosaurs than with modern birds.Archaeopteryx was generally accepted by palaeontologists and popular reference books as the oldest known bird.Archaeopteryx could grow to about 0.5 m (1 ft 8 in) in length.

I hope it help

6 0
1 year ago
What did you observe in the reaction of phosphoric acid with the freshly cleaned zinc when compared with a piece just taken out
mash [69]

Answer:

The classification is mentioned below for the particular topic.

Explanation:

  • Whether we position 2 different beakers in such a single beaker through one clean edge of zinc-containing H₃Po₄ and another one with unflushed zinc.  
  • The zinc that was washed set to release hydrogen gas way quicker, unlike unventilated zinc.  

⇒      3Zn+2H_{3}Po_{4}\rightarrow Zn_{3}(Po_{4})_{2}+3H_{2}

  • Since fresh zinc complicates the cycle since, as a comparison to polluted zinc, there was little contact with either the reaction.
6 0
3 years ago
State which separation method you would use to separate potassium iodine solution​
navik [9.2K]
Could be separated by distillation.
3 0
2 years ago
How much heat energy is needed to heat 300g of water from 10 degrees Celsius to 50 degrees Celsius
elixir [45]

Answer:

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

Explanation:

<u>Step 1: </u>Data given

mass of water = 300 grams

initial temperature = 10°C

final temperature = 50°C

Temperature rise = 50 °C - 10 °C = 40 °C

Specific heat capacity of water = 4.184 J/g °C

<u>Step 2:</u> Calculate the heat

Q = m*c*ΔT

Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)

Q = 50208 Joule = 50.2 kJ

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

8 0
2 years ago
BRAINLIESTTT ASAP!!! PLEASE HELP ME :))
lys-0071 [83]

Answer:

Multiply 1.25 by 0.04 and divide the result obtained by 1,000

Explanation:

Since there is .04 oz in 1 gram, we take the 1.25 gram and multiply by .04.

Next, to convert per liter to per milliliter, we divide by 1,000.

3 0
3 years ago
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