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3 years ago

9

Given a stock standard solution of concentration 0.200 M, calculate the volume in mL required to make up calibration standards o

f the following concentrations (in 25.0 mL volumetric flasks)
1.60 x 10-2 M .....mL

1 answer:

guapka [62]3 years ago

6 0

M1V1 = M2V2

.200 (.025) = 1.60 X 10 -2 (V2)

V2 = .315 L

1.60 x 10-2 M in 315 mL

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According to Le Chatelier’s principle, what happens when the concentration of reactants is doubled in a chemical reaction that w

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If more reactant is added, the equation will shift to the right in order to make more product (which will increase the products)

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How would a solution that is labeled 5.0 M would be read as?

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5 moles because molarity signifies number of moles dissolved in One litre of water

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When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

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3 years ago

NEED QUICK ANSWERS ( science)

nata0808 [166]

Answer:

Explanation:

"Nature does this job through a process called the water cycle. Also known as hydrologic cycle, the water cycle is a phenomenon where water moves through the three phases (gas, liquid and solid) over the four spheres (atmosphere, lithosphere, hydrosphere and biosphere) and completes a full cycle. The water cycle has many effects: it regulates the temperature of the surroundings. It changes weather and creates rain. It helps in conversion of rocks to soil. It circulates important minerals through the spheres. It also creates the many geographical features present on earth like the ice caps of mountains, icebergs, the rivers and the valleys, lakes, and more. Hence it is quite important to understand and learn the processes of the water cycle."

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3 years ago

List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)

Leokris [45]

<u>Answer:</u>

<em>20, 44, 62 </em>

<em></em>

<u>Explanation:</u>

To find the number of atoms of each element, we multiply coefficient and subscript

For example $5 Ca_1 Cl_2$ contains

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example $3Ca_3 (P_1 O_4 )_2$

we multiply coefficient × subscript × number outside the bracket to find the number of atoms

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

So let us find the number of atoms of each element on the left side of the equation

$2C_{10} H_{22} (l)+31O_2 (g)\Rightarrow 20CO_2 (g)+22H_2 O(g)$

Number of C atoms = 2 × 10 = 20

Number of H atoms = 2 × 22 = 44

Number of O atoms = 31 × 2 = 62

20, 44, 62 are the Answers.

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3 years ago