Answer:
![m=8.79kg](https://tex.z-dn.net/?f=m%3D8.79kg)
Explanation:
First of all we need to calculate the heat that the water in the cooler is able to release:
![Q=\rho * V*Cp*\Delta T](https://tex.z-dn.net/?f=Q%3D%5Crho%20%2A%20V%2ACp%2A%5CDelta%20T)
Where:
- Cp is the mass heat capacity of water
- V is the volume
is the density
![Q=1 g/cm^3 *15000 cm^3*4.184 \frac{J}{g*^{\circ}C}*(10-90)^{\circ}C](https://tex.z-dn.net/?f=Q%3D1%20g%2Fcm%5E3%20%2A15000%20cm%5E3%2A4.184%20%5Cfrac%7BJ%7D%7Bg%2A%5E%7B%5Ccirc%7DC%7D%2A%2810-90%29%5E%7B%5Ccirc%7DC)
![Q=-5020800 J=-5020.8 kJ](https://tex.z-dn.net/?f=Q%3D-5020800%20J%3D-5020.8%20kJ)
To calculate the mass of CO2 that sublimes:
![-Q=\Delta H_{sub}*m](https://tex.z-dn.net/?f=-Q%3D%5CDelta%20H_%7Bsub%7D%2Am)
Knowing that the enthalpy of sublimation for the CO2 is: ![\Delta H_{sub}=571 kJ/kg](https://tex.z-dn.net/?f=%5CDelta%20H_%7Bsub%7D%3D571%20kJ%2Fkg)
![5020.8 kJ=571 kJ/kg*m](https://tex.z-dn.net/?f=5020.8%20kJ%3D571%20kJ%2Fkg%2Am)
![m=\frac{5020.8 kJ}{571 kJ/kg}=8.79kg](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B5020.8%20kJ%7D%7B571%20kJ%2Fkg%7D%3D8.79kg)
I need a a picture or the question
Answer:
The correct answer is A
Explanation:
That water stops moving once it gets to the dam and turns into potential energy
Answer:
0.35714 Metric ton
Explanation:
350 / 0.98 = 357.1 ----------A
to get the answer on metric ton divide (a) by 1000
357.14/1000= 0.357
It does<span>, however, change the </span>mass<span> of the nucleus. </span>Adding<span> or removing </span>neutrons<span>from the nucleus are how isotopes are created. Protons carry a positive electrical charge and they alone determine the charge of the nucleus.</span>